it wil giv an exception -compiler exception

It will run fine with no exception here is the example :

public class CheckException extends Thread{
	public CheckException(){
		super.start();
		this.start();
	}
@Override
public synchronized void start() {
	// TODO Auto-generated method stub
	super.start();
}
}

wont there be any stack overflow?

The question clearly specifies "what happen if u _CALL_
super and this in the same class"

By call, probably, they mean:
   this();  /*Invoking the constructor*/
   super(); /*Invoking the parent class's constructor*/

I think the right answer is that it will raise a compiler
exception. Such a program will not compile.

We can't give both super() and this()in a constructor,
because both of these statements must be the first
statements in constructor. if you give super() as the first
statement then compiler error will come with this() call.
and vice versa.
but you can call the members with both super and this in a
constructor. here is the code.
class Base
{
	Base()
	{
		System.out.println("Base constructor");
	}
	void m1()
	{
		System.out.println("m1 of Base");
	}
}
class Derived extends Base
{
	Derived()
	{
		super();//it is ok.
		this();//raises compiler error 
      //but we can call the members with super and this 
            super().m1();//make sure that   super()in      
line must be marked comment
            this().m1();
	System.out.println("Derived constructor");
		}
	void m1()
	{
		System.out.println("m1 of Derived");
	}
	public static void main(String[] args) 
	{
	Derived d=new Derived();
	}
}
it works out

No it doesn't work I have just tested