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Question
#include<stdio.h>
main()
{
	char *p1;
	char *p2;
	p1=(char *) malloc(25);
	p2=(char *) malloc(25);
	strcpy(p1,"Ramco");
	strcpy(p2,"Systems");
	strcat(p1,p2);
	printf("%s",p1);
}

Tell me the output?
 Question Submitted By :: Naveed
I also faced this Question!!     Rank Answer Posted By  
 
  Re: #include<stdio.h> main() { char *p1; char *p2; p1=(char *) malloc(25); p2=(char *) malloc(25); strcpy(p1,"Ramco"); strcpy(p2,"Systems"); strcat(p1,p2); printf("%s",p1); } Tell me the output?
Answer
# 1
25Ramco25Systems
 
Is This Answer Correct ?    0 Yes 0 No
Mastan Vali.shaik
 
  Re: #include<stdio.h> main() { char *p1; char *p2; p1=(char *) malloc(25); p2=(char *) malloc(25); strcpy(p1,"Ramco"); strcpy(p2,"Systems"); strcat(p1,p2); printf("%s",p1); } Tell me the output?
Answer
# 2
The output will b : RamcoSystems
 
Is This Answer Correct ?    0 Yes 0 No
Fazlur Rahaman Naik
 
 
 
  Re: #include<stdio.h> main() { char *p1; char *p2; p1=(char *) malloc(25); p2=(char *) malloc(25); strcpy(p1,"Ramco"); strcpy(p2,"Systems"); strcat(p1,p2); printf("%s",p1); } Tell me the output?
Answer
# 3
the output will be RamcoSystems
but we need 2 more libraries
#include<string.h> and
#include<alloc.h>
to run this program. in else case it will not work.
 
Is This Answer Correct ?    0 Yes 0 No
Sumant
 
  Re: #include<stdio.h> main() { char *p1; char *p2; p1=(char *) malloc(25); p2=(char *) malloc(25); strcpy(p1,"Ramco"); strcpy(p2,"Systems"); strcat(p1,p2); printf("%s",p1); } Tell me the output?
Answer
# 4
#include<stdio.h>

main()
{
        char *p1,*p2;
        p1 = (char *)malloc(25);
        p2 = (char *)malloc(25);
        strcpy(p1,"Ramco");
        strcpy(p2,"Systems");
        strcat(p1,p2);
        printf("%s",p1);
}



the output will be RamcoSystems

we don't need the following libraries under Linux 2.6
#include<string.h> and
#include<alloc.h>
to run this program.
 
Is This Answer Correct ?    0 Yes 0 No
V.srinivasan
 

 
 
 
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