At the time of starting a tube choke gives rise to high
voltage by di/dt nearly 1000 volts by starter ON-OFF
function rate of change of voltage becomes high due to
inductance of choke. This high voltage starts ionization of
gas in the tube. Once gas gets ionised and starts
conducting then starter gets out of circuit and circuit is
completed only through choke which now share voltage(limit
voltage) for tube because after esabilishing ionization now
to maintain it only nearly half of the voltage is required.

The function of choke is to provide high voltage enough for
ionization to take place in a tube light and after
establishment and substenance of ionization, limit the
voltage across the tube. That is the reason why a tube
fuses when the choke is shorted.

To start the tubelight. we have to ionise the gas inside
tubelight like murcury which ionise at high voltage around
1000 to 1500 V it is provided by choke.

the property of the inductor is to oppose the rate of
change of current through it suddenly. At the time of
starting it requires high voltage to ionise the gas (
through creating potential difference between the
electrodes) in the tube so choke creates required potential.
The starter is same as that of a capacitor, to improve the
power factor the total system(connection of R and L) it is
required.

Hi frnds :)
plz tell me that i have 100 KVA 3 phase generator so by
thumb rule 100*1.4 = 144 amps
and generaly we can operate at 80% load...so it will 144*0.8
=112 amps....
so now i m confused about single phase load.....if we use
that generator only for single phase the that 112 amps is
total single phase load or i can give 112 amps at red 112
amps at yellow and 112 amps at blue....
i mean that total single phase load that 100 KVA generator
will take is 112+112+112=336 amp ??

What will be the resultant out put voltage when two
different voltage rating batteries are vconnected in
parallel? pls. answer with example if available.