The postfix ++ and -- operators essentially have higher
precedence than the prefix unary operators. Therefore, *i++
is equivalent to *(i++); it increments i, and returns the
value which i pointed to before i was incremented. To
increment the value pointed to by i, use (*i)++ (or perhaps
++*i, if the evaluation order of the side effect doesn't
matter).
i++* wont work .... as for as i know.... it's meaningless
comin to *++i, i is a pointer holding an address so here ++
and * holds the same priority so we ll go for associativity
of these operators. it's RIGHT to LEFT.
so , address in 'i' will get incremented and then if that
address points to some value means it will print that value
or else it will have garbage value
In case of i++, it'll first assign the value of i and then
increment it's value by one. But in case of ++i, it 'll
first increment the value of i by 1 and then assign the new
value of i.This is the difference between i++ and ++i.
*++i
assuming i is declared as pointer
i will be first incremented to point to next location to
which it is pointing. then, the content of location to
which i is newly pointing will be assigned if any variable
is used like: a=*++i;
here since it is not assigned to any variable it will be
dicard.
i++*
if the statement is int a=i++*;
then i is incremented to point to next location of its type
then the content of that location is being copied to a
using *.
write an algorithm to get a sentence and reverse it in the
following format:
input : I am here
opuput: Here Am I
note: first letter of every word is capiatlised
How to find the digits truncation when assigning the
interger variable to the character variables.
like int i=500; char x = i : here we have truncation. how to
find this.
another ex: i =100; char x=i. here we do not have
truncation.
Ask Questions on ANYTHING, that arise in your Daily Life at 
Site Map
