The o/p will be as follows:-

                  666

reason:- in c++ in cascading the processing will be from
RHS. hence first "++i" will be executed and gives value 6.
after that "i" is executed as 6 and finally "i++" which will
also give 6.

one thing to notice here is that printing will be as usual
i.e. from left to right. So if the structure was "++i i i++"
then o/p will be 765

The output is 7

The answer is undefined since you are modifying a built in 
type in sequence without a sequence point in between.

my answer is 755........

My answer is 
1. 
#include<iostream>
using namespace std;
int main()
{
	int i = 5;
	cout << ++i << i << i++ << endl;
	return 0;
}
ANS:765

2. 
#include<iostream>
using namespace std;
int main()
{
	int i = 5;
	cout << ++i ;
	cout << i ;
	cout << i++ << endl;
        return 0;
}
ANS:666