Using sizeof() operator.


if(sizeof(no)==2)
 cout<<"no is int";
else 
 cout<<"float";

incomplete solution.
why? what if no is "long int" or "double"?
in that case his solution will always print float.

bool __inline is_integer(float f){
    int i = f;
    return (f == static_cast<float>(i));
} 


int main()
{
	int num=0;
	double num2= 1234;

	num=num2;

	if(is_integer(num2))

		printf("the number is int");
	else
		printf("the number is float");

	getch();

	
	return 0;
	
}

if(sizeof(no)==2)
  cout<<"Integer";
else if(sizeof(no)==4)
  cout<<"Float";

one way according to me is to find through the no. of bytes allocated for that variable or the value itself directly...........


thank u