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Use template column and put image as control in the 
itemTemplate

initially while inserting image into database take the 
database field in oracle as BLOB in sql as image

during insertion convert the image file into bytes and 
insert it into the database

during the display of image in datagrid take a image 
template and display the converted values
sample code to get the image:
public byte[] spic(string cm,int id)
        {
            con = new OracleConnection(cm);
            OracleCommand cmd = new OracleCommand("select 
photo from kir_image where eid= "+id +" ", con);
            con.Open();
            byte[] img = (byte[])cmd.ExecuteScalar();
            con.Close();
            return img;
        }

use Response.BinaryWrite to display the image

Using C#(Asp.net)
-------------
 <asp:TemplateColumn HeaderText ="Photo" >
      <ItemTemplate>
<asp:image
      
      </ItemTemplate>
     <asp:Image ID="udphoto" ImageUrl='<%#Eval("Photo")%>'
runat="server" />
      <HeaderStyle ForeColor ="blue" />
      </asp:TemplateColumn>

Using Vb.Net(Asp.net)
-------------
<asp:TemplateColumn HeaderText ="Photo" >
      <ItemTemplate>
<asp:image
      
      </ItemTemplate>
     <asp:Image ID="udphoto"
ImageUrl='<%#DataBinder.Eval(Container.DataItem,"Photo")%>'
runat="server" />
      <HeaderStyle ForeColor ="blue" />
      </asp:TemplateColumn>