The cooling produced by melting of 1 ton of ice in a day is
taken as unit of refrigeration (in tons). Now unit of
refrigeration used in S.I. System is KW.
1 ton of refrigeration
= mass of ice x latent heat of ice / 24 hrs
= 900 kg x 335 KJ/Kg ( one short ton = 900 kgs )
24 x 3600 secs
= 3.4895 KJ/Sec
say 3.5 KJ / Sec = 3.5 KW
how can we minimize the off load losses of a distribution
transformer which is required to be energized 24x7 ??
capacity of the T/F is 1250 KVA and off load losses are
around 2.0 KW.. can we use capacitor bank at the secondary
of such a T/F to overcome off load losses? please elaborate