| Other C Code Interview Questions |
| |
| Question | Asked @ | Answers |
| |
| #include<stdio.h>
main()
{
char s[]={'a','b','c','\n','c','\0'};
char *p,*str,*str1;
p=&s[3];
str=p;
str1=s;
printf("%d",++*p + ++*str1-32);
} | | 1 |
| main()
{
char *p="hai friends",*p1;
p1=p;
while(*p!='\0') ++*p++;
printf("%s %s",p,p1);
} | | 1 |
| Write a routine to draw a circle (x ** 2 + y ** 2 = r ** 2)
without making use of any floating point computations at all. | Microsoft | 2 |
| main()
{
if ((1||0) && (0||1))
{
printf("OK I am done.");
}
else
{
printf("OK I am gone.");
}
}
a. OK I am done
b. OK I am gone
c. compile error
d. none of the above | HCL | 1 |
| What is the subtle error in the following code segment?
void fun(int n, int arr[])
{
int *p=0;
int i=0;
while(i++<n)
p = &arr[i];
*p = 0;
} | | 1 |
| void main()
{
char a[]="12345\0";
int i=strlen(a);
printf("here in 3 %d\n",++i);
} | | 1 |
| main( )
{
char *q;
int j;
for (j=0; j<3; j++) scanf(“%s” ,(q+j));
for (j=0; j<3; j++) printf(“%c” ,*(q+j));
for (j=0; j<3; j++) printf(“%s” ,(q+j));
} | | 1 |
| main()
{
char *p="GOOD";
char a[ ]="GOOD";
printf("\n sizeof(p) = %d, sizeof(*p) = %d, strlen(p) = %d",
sizeof(p), sizeof(*p), strlen(p));
printf("\n sizeof(a) = %d, strlen(a) = %d",
sizeof(a), strlen(a));
} | | 1 |
| main()
{
float me = 1.1;
double you = 1.1;
if(me==you)
printf("I love U");
else
printf("I hate U");
} | | 1 |
| main()
{
char c;
int i = 456;
clrscr();
c = i;
printf("%d", c);
}
a. 456
b. -456
c. random number
d. none of the above | HCL | 1 |
| #if something == 0
int some=0;
#endif
main()
{
int thing = 0;
printf("%d %d\n", some ,thing);
} | | 1 |
| main()
{
int i=0;
for(;i++;printf("%d",i)) ;
printf("%d",i);
} | | 1 |
| program to Reverse a linked list | Ness-Technologies | 4 |
| Print an integer using only putchar. Try doing it without
using extra storage. | | 1 |
| How will u find whether a linked list has a loop or not? | Microsoft | 6 |
| main()
{
int a=2,*f1,*f2;
f1=f2=&a;
*f2+=*f2+=a+=2.5;
printf("\n%d %d %d",a,*f1,*f2);
} | | 1 |
| Finding a number which was log of base 2 | NetApp | 1 |
| How will you print % character?
a. printf(“\%”)
b. printf(“\\%”)
c. printf(“%%”)
d. printf(“\%%”) | HCL | 1 |
| main()
{
int i=10,j=20;
j = i, j?(i,j)?i:j:j;
printf("%d %d",i,j);
} | | 1 |
| Given an array of characters which form a sentence of
words, give an efficient algorithm to reverse the order of
the words (not characters) in it.
| Microsoft | 6 |
| |
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