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Categories  >>  ERRORS  >>  C C++ Errors
 
 


 

 
 C C++ Errors interview questions  C C++ Errors Interview Questions
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Question
loop1:
{
 x=i<n?(i++):0;
 printf("%d",i);
 exit(x);
 continue;
}
Error- misplaced continue.
Doubt-1.will the exit(x) be executed for all values of x
      2.will this statement go out of the program.

 
 Question Submitted By :: Srividhya
I also faced this Question!!     Rank Answer Posted By  
 
  Re: loop1: { x=i<n?(i++):0; printf("%d",i); exit(x); continue; } Error- misplaced continue. Doubt-1.will the exit(x) be executed for all values of x 2.will this statement go out of the program.
Answer
# 1
Error- misplaced continue.
 
Is This Answer Correct ?    0 Yes 0 No
Srinivas
 
  Re: loop1: { x=i<n?(i++):0; printf("%d",i); exit(x); continue; } Error- misplaced continue. Doubt-1.will the exit(x) be executed for all values of x 2.will this statement go out of the program.
Answer
# 2
Dear SRIVIDYA!!!!

as per my experience....
exit() function can take only two arguments. 0(zero) and 1

exit(0)--indicates exit with error
exit(1)--indicates successful exit...

coming to yr code fragment in question..there is a 
possibility for exit(x) to take other values..

so this caused the errorrrrr

-------------------------

correct me if its wrong!!


yours vijayabhaskar83@sifymail.com
 
Is This Answer Correct ?    0 Yes 0 No
Vija
 
 
 
  Re: loop1: { x=i<n?(i++):0; printf("%d",i); exit(x); continue; } Error- misplaced continue. Doubt-1.will the exit(x) be executed for all values of x 2.will this statement go out of the program.
Answer
# 3
HI,

1: the statement x=i<n?(i++):0;
       the value of i is < n the i will be increamented  
by     1, else 0.
2 : The value of i is printed.
3 : exit() function is executed by all values of x.
4 : this program will not go out of loop.
 
Is This Answer Correct ?    0 Yes 0 No
Padmaraj
 

 
 
 
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