infinite loop

in each iteration it will print the characters for ascii
values 0,1,2,3,...

I think it will print ascii values of 0,1,2 and so on upto 1000

It will print funny caharcter ( ascii equivalent of 1000 
trucated char) infinitely

In each iteration the equivalent ascii values of 0 to 1000 
will print.

it show compliation error

This will print the ascii characters from 0 to 1000 if the
datat type of the variable c is other than character. If the
datatype of the variable is char then it will be into
infinite loop.

It print's only what's the ASCII value of 1000 for infinite loop

answer 6 is absolutely correct

It will give a compilation error..

the for loop syntax is
for(initialize; condition ; inc / dec)

condition -> assignment operator is wrong..

there should be 2 equals ("==")..

it will come out of the for loop & hence no output.
because,when c=0,then for next condition it will check
whether 0==1000,the condition fails here itself only.
so,it doesn't go for executing any statement.

The output of the given program is the character or ascii 
value of 0,1,2,..........so on up to the stack of memory 
get full.The reason behind it is the condition for 
termination is not given in the for loop,because c=1000 is 
assingment operator not a conditional.

warning occurs as possibly incorrect statement.
and the statement falls into infinite loop printing the 
ascii character equivalent to 0

i executed this program it went on displaying funny
characters indefinite loop

It goes into an infinite loop.

The compiler will check only the syntax, it is upto the 
programmer to implement correct logic.

other than initialization, c is always 1000 and there is no 
condition to be break the loop

it will goto infinite loop because each time i=0 and i=100 
so it will goto infinite loop.

It will go for infinite loop. 
But in each iteration, c is assigned with the value 1000.
So each time it will print a character of ascii=1000.

Warnings: 

Test expression for for is assignment expression: c = 1000
The condition test is an assignment expression. Probably,
you mean to use == instead of =. If an assignment is
intended, add an extra parentheses nesting(e.g., if ((a =
b)) ...) to suppress this message. (Use -predassign to 
inhibit warning)

Test expression for for not boolean, type int: c = 1000.
Test expression type is not boolean or int. (Use
-predboolint to inhibit warning)