23

27

hellooo
can u pls explain it
thnx

number me 
integers 
between then is 
=51                         
the number of 
integers divided 
by 3 of the 
numbers 
=17           
numere of 
integers divided 
by 5 of
 there number 
=11                              
number OF 
integers divided 
by both =4 
so that 
17+11_4=24     
and 51-24=27

49-16-9+3=27

the numbers between 100 and 150 are 51
51-17-10+3=29

27

its 23

its 27 because the no divisible by three is 17 and that by 
5 is 11 common nos for both will be 4 hence our ans will be 
neither for 5 nor for three therfore it is 49-17-11-4=27

ans=24
no divisible by 3:
102,105,108,111,114,117,120,123,126,129,132,135,138,141,144,
147,150.
no divisible by 5:
100,105,110,115,120,125,130,135,140,145,150.

now strike out 105 120 135 150,as it is present in 
both.remaining totally 24 nos are present,which cannot be 
evenly divided 3 or 5.(means wen divisible by 3 it is not 
by 5 n vice versa)

ans=4
no divisible by 3:17
A =
{102,105,108,111,114,117,120,123,126,129,132,135,138,141,144
,147,150}

no divisible by 5: 11
B= {100,105,110,115,120,125,130,135,140,145,150}

3 nor 5 means ^(AvB)

So, AvB = 25
^(AvB) = 4
now strike out 105 120 135 150,as it is present in 
both.remaining totally 24 nos are present,which cannot be 
evenly divided 3 or 5.(means wen divisible by 3 it is not 
by 5 n vice versa)

ans:27
there are 24 numbers which are divisible by
both 3 and 5.
51-24=27

21