abcD+abcd+aBCd+aBCD then the simplified function is ( Capital let

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abcD+abcd+aBCd+aBCD
    then the simplified function is
    ( Capital letters are copliments of corresponding letters
      A=compliment of a)
 
   [a] a   [b] ab  [c] abc  [d] a(bc)* [e] mone
   (bc)*=compliment of bc

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Re: abcD+abcd+aBCd+aBCD then the simplified function is ( Capital letters are copliments of corresponding letters A=compliment of a) [a] a [b] ab [c] abc [d] a(bc)* [e] mone (bc)*=compliment of bc

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Re: abcD+abcd+aBCd+aBCD then the simplified function is ( Capital letters are copliments of corresponding letters A=compliment of a) [a] a [b] ab [c] abc [d] a(bc)* [e] mone (bc)*=compliment of bc

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# 2

since capital letters are the complements...
(abcD+abcd)+(aBCd+aBCD)..taking them separately...
solving for the 1st bracket...abc(D+d)=abc{D+d=0}
solving for the 2nd bracket...aBC(d+D)=aBC{D+d=0}
==abc+aBC=a(bc+BC)
         =a*0
         =0

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Ramya

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