What will be the result of the following program?
main()
{
char p[]="String";
int x=0;
if(p=="String")
{
printf("Pass 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
else
{
printf("Fail 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
}
a) Pass 1, Pass 2
b) Fail 1, Fail 2
c) Pass 1, Fail 2
d) Fail 1, Pass 2
e) syntax error during compilation
Re: What will be the result of the following program?
main()
{
char p[]="String";
int x=0;
if(p=="String")
{
printf("Pass 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
else
{
printf("Fail 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
}
a) Pass 1, Pass 2
b) Fail 1, Fail 2
c) Pass 1, Fail 2
d) Fail 1, Pass 2
e) syntax error during compilation
Re: What will be the result of the following program?
main()
{
char p[]="String";
int x=0;
if(p=="String")
{
printf("Pass 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
else
{
printf("Fail 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
}
a) Pass 1, Pass 2
b) Fail 1, Fail 2
c) Pass 1, Fail 2
d) Fail 1, Pass 2
e) syntax error during compilation
Re: What will be the result of the following program?
main()
{
char p[]="String";
int x=0;
if(p=="String")
{
printf("Pass 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
else
{
printf("Fail 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
}
a) Pass 1, Pass 2
b) Fail 1, Fail 2
c) Pass 1, Fail 2
d) Fail 1, Pass 2
e) syntax error during compilation
Re: What will be the result of the following program?
main()
{
char p[]="String";
int x=0;
if(p=="String")
{
printf("Pass 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
else
{
printf("Fail 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
}
a) Pass 1, Pass 2
b) Fail 1, Fail 2
c) Pass 1, Fail 2
d) Fail 1, Pass 2
e) syntax error during compilation
Re: What will be the result of the following program?
main()
{
char p[]="String";
int x=0;
if(p=="String")
{
printf("Pass 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
else
{
printf("Fail 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
}
a) Pass 1, Pass 2
b) Fail 1, Fail 2
c) Pass 1, Fail 2
d) Fail 1, Pass 2
e) syntax error during compilation
Re: What will be the result of the following program?
main()
{
char p[]="String";
int x=0;
if(p=="String")
{
printf("Pass 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
else
{
printf("Fail 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
}
a) Pass 1, Pass 2
b) Fail 1, Fail 2
c) Pass 1, Fail 2
d) Fail 1, Pass 2
e) syntax error during compilation
Re: What will be the result of the following program?
main()
{
char p[]="String";
int x=0;
if(p=="String")
{
printf("Pass 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
else
{
printf("Fail 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
}
a) Pass 1, Pass 2
b) Fail 1, Fail 2
c) Pass 1, Fail 2
d) Fail 1, Pass 2
e) syntax error during compilation
Re: What will be the result of the following program?
main()
{
char p[]="String";
int x=0;
if(p=="String")
{
printf("Pass 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
else
{
printf("Fail 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
}
a) Pass 1, Pass 2
b) Fail 1, Fail 2
c) Pass 1, Fail 2
d) Fail 1, Pass 2
e) syntax error during compilation
Fail 1 , Pass 2.
Some explanation,
1. Fail 1
first of all, to compare strings in C, you use this strcmp
function, so this WOULD give PASS 1 :
if(strcmp(p,"String") == 0)
but
if(p=="String")
will fail because this line means :
if address of p is the same as address of some temporary
storage for literals, where literal "String" is stored,
which is very rarely true, because storing literals is
compiler specific and is very hard to estimate at runtime.
2. Pass 2
sizeof(p) gives 7, because sizeof(char) is 1 byte, and we
have 7 chars in array storing "String", which are :
[0]S
[1]t
[2]r
[3]i
[4]n
[5]g
[6]\0 (EOS)
now, clearly sizeof(p) - 2 is [5] which is "g"
thats why
if(p[sizeof(p)-2]=='g')
is true.
Re: What will be the result of the following program?
main()
{
char p[]="String";
int x=0;
if(p=="String")
{
printf("Pass 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
else
{
printf("Fail 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
}
a) Pass 1, Pass 2
b) Fail 1, Fail 2
c) Pass 1, Fail 2
d) Fail 1, Pass 2
e) syntax error during compilation
syntax error during compilation..
we cannot compare strings using if(p == "string")
so will not work..
NOTE:
while comparing string otherwise also we use 'string'
(string in single quotes ' ' not " ")..
Re: What will be the result of the following program?
main()
{
char p[]="String";
int x=0;
if(p=="String")
{
printf("Pass 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
else
{
printf("Fail 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
}
a) Pass 1, Pass 2
b) Fail 1, Fail 2
c) Pass 1, Fail 2
d) Fail 1, Pass 2
e) syntax error during compilation
b)fail1,fail2
bcoz whenever we compare strings,we use strcmp()
function,hence the condition in if() will not be true,
the control will go into else part and will print fail1,then
size of array p is 6 and sizeof(p)-2 results to 4 and hence
p[4]=='n'which again makes the condition in the if()
false,hence fail2 in else part will be printed.
thnx
Look at the Code:
main()
{
int a[]={1,2,3},i;
for(i=0;i<3;i++)
{
printf("%d",*a);
a++;
}
}
Which Statement is/are True w.r.t the above code?
I.Executes Successfully & Prints the contents of the array
II.Gives the Error:Lvalue Required
III.The address of the array should not be changed
IV.None of the Above.
A)Only I B)Only II C)II & III D)IV
a.One Cannot Take the address of a Bit Field
b.bit fields cannot be arrayed
c.Bit-Fields are machine Dependant
d.Bit-fields cannot be declared as static
Which of the Following Statements are true w.r.t Bit-Fields
A)a,b&c B)Only a & b C)Only c D)All
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