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 General Aptitude interview questions  General Aptitude Interview Questions (1893)
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A room is 30 X 12 X 12. a spider is ont the middle of the
samller wall, 1 feet from the top, and a fly is ont he
middle of the opposite wall 1 feet from the bottom. what is
the min distance reqd for the spider to crawl to the fly.
 Question Submitted By :: General-Aptitude
I also faced this Question!!     Answer Posted By  
# 1
length is 30 breadth is 12 and height is 12
1 .
1 .
1 10 .
1 .
1 30 .
consider right angled triangle
so the distance= square root of (30*30+10*10)
Is This Answer Correct ?    6 Yes 3 No
# 2
h=30; b=12; h=12;

| " |
| |
| | 12
| |
| " |

Apply Geometry to get the minimum distance.

Mid-point [A] of side wall is at 6.
Spider [B] is at 5 from Mid-point of side wall (or) 11 from bottom (or) 1 form top.
Center point [C] of box is 15 away form the mid-point of side wall.

Then ABC is a right angled triangle.
Sides AB=5; AC=15;
Angle at A=90 degrees

Mid-point[D] of ooposite sidewall is at 6.
Fly [E] is at 5 from Mid-point of opposite side wall (or) 11 from top (or) 1 form bottom.
Center point [C] of box is 15 away form the mid-point of opposite side wall.

Then DEC is a right angled triangle.
Sides DE=5; DC=15;
Angle at D=90 degrees

Shortest distance from B(Spider) to E(Fly)
BE = BC + CE
BE = 31.622
Is This Answer Correct ?    3 Yes 0 No
# 3
1 1
1" 1
1 1
1 " 1

i hope u get the diagram

its 11+30+1=42units
Is This Answer Correct ?    9 Yes 8 No

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