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Question
what is the difference between stress and pressure?. what 
is the difference between moment and torque?
 Question Submitted By :: Guest
I also faced this Question!!     Rank Answer Posted By  
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 1
difference between stress and pressure

stress=resistive force/area.

pressure=force/area.
 
Is This Answer Correct ?    9 Yes 4 No
Bhupendra Sahu
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 2
stress is nothing but load/area and pressure is the force 
acting in any one direction
 
Is This Answer Correct ?    1 Yes 7 No
Guest
 
 
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 3
STRESS= the internal resistance developed due to the
application of external force.


PRESSURE=force per unit area
 
Is This Answer Correct ?    6 Yes 2 No
Shams Parwez
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 4
We know that every materials is elastic in nature , so when 
a force is applied it tends to deform and due to this 
deformation , there is an internal resistance produced 
which tends to spring back the molecules to their original 
position and this internal resistance per unit area is know 
as STRESS .

Pressure is nothing but force acting on a unit area .
 
Is This Answer Correct ?    13 Yes 0 No
Nitin
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 5
Torque is the rotational force acting on a component around 
its axis

A moment is the force acting on a component horizontally 
through its axis
 
Is This Answer Correct ?    2 Yes 2 No
Slammindan
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 6
stress is internal reaction where as pressure is external..
 
Is This Answer Correct ?    4 Yes 1 No
Banke Bihari
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 7
stress is internal resisance to external load where as 
pressure is external force applied upon the surface
 
Is This Answer Correct ?    5 Yes 1 No
Shashikanth S S
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 8
Stress is nothing but internal resistive force to 
deformation per unit cross sectional area. It is always 
perpendicular to the surface.
Pressure is Force per unit area. It is always parallel to 
the surface.
 
Is This Answer Correct ?    1 Yes 4 No
Amolkumar
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 9
stress and pressure are mathmetically same.
but stress is term used in solids 
while pressure is used in fluids.
 
Is This Answer Correct ?    3 Yes 1 No
Psg Tech
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 10
when a force acting on a body, a force created inside body 
that is called stress, the force acting on the body is 
called pressure,
 
Is This Answer Correct ?    1 Yes 1 No
Harisankar.j
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 11
for example if we take any rod and when we bend that it 
wont deform initially. bcoz there is some internal 
resistance will act against the deformation. That internal 
resistance is called as stress.pressure is nothing but the 
force what we are giving initially to bend that rod.

moment is the twisting force
but torque is one of the twisting moment.
 
Is This Answer Correct ?    1 Yes 0 No
Ramji
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 12
Stress s for the solid materials and pressure s for liquid
and gases... both are load/force per unit area only
 
Is This Answer Correct ?    2 Yes 0 No
Sivabharathi
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 13
stress is the internal resistance set by the molecule.
          stress=load/area
 
pressure=force/area

stress may be in tension or compression or shear.
pressure is only in compression
 
Is This Answer Correct ?    2 Yes 0 No
Bindeshwari Pal
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 14
stress is a vector quantity where as presser is a scalar
similarly 
torque is a vector where as moment is a scalar
 
Is This Answer Correct ?    2 Yes 0 No
Ashutosh
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 15
why should i tell u? Think over it and tell me.
 
Is This Answer Correct ?    4 Yes 2 No
Abcd
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 16
Moment is due to Bending of the shaft or the given material
And torque is developed due to rotation of the shafte.
 
Is This Answer Correct ?    1 Yes 0 No
Gurmeet Singh
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 17
stress is the internal resistance caused by body when it is 
subjected by any load.
But pressure is the external force act on the body.It 
doesn't help to know the body whether it can withstand the 
load or not.But the earlier helps for it.
 
Is This Answer Correct ?    1 Yes 0 No
Bala
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 18
stress is internal distribution of force per unit area
against external forces.pressure is a external force applied
perpendicular to the surface per unit area
 
Is This Answer Correct ?    1 Yes 0 No
J.ravi
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 19
stress....internal resistive force/ area.......
pressure external force/area....

moment....due to bending....like a horizontal shaft being
acted upon by a vertical force.....force *distance(where the
shaft is been supported like in cantilever case)

torque....a force* distance....this distance is b/w the
force      acing line and the axis of the shaft....
 
Is This Answer Correct ?    1 Yes 0 No
Manoj
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 20
difference between stress and pressure
stress=resistive force/area.
pressure=force/area.

stress is nothing but load/area and pressure is the force 
acting in any one direction
 
Is This Answer Correct ?    0 Yes 0 No
Guest
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 21
what scalar & vector peopole are talking off?

Stress is force experienced internally 
while pressure is something which works externally.
Like only in case of metals we talk of stress which have 
ductility
 
Is This Answer Correct ?    1 Yes 0 No
Guest
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 22
the stress is the internal effect of a body and pressure is
applied externally
 
Is This Answer Correct ?    0 Yes 0 No
Kashif
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 23
Pressure (symbol: p) is the force per unit area applied on 
a surface in a direction perpendicular to that surface. 
Mathematically:


where:


p is the pressure 
F is the normal force 
A is the area. 
Pressure is transmitted to solid boundaries or across 
arbitrary sections of fluid normal to these boundaries or 
sections at every point. It is a fundamental parameter in 
thermodynamics and it is conjugate to volume.
Moments is the scientific name given to someting that turns 
on a pivot (fulcrum). The pressure of the moment can also 
be measured using a similar calculation to one given 
earlier in this article. The thing to consider or the 
relationship is that the further away the load (effort 
force) is from the pivot the larger the force. For example, 
a door, it has its handle (effort force) right at the end 
furthest away from the hinges (pivot). This allows the door 
to move with ease. The calculation used to measure force of 
moments is:

Distance from Pivot (mm/cm/m/km/M) X Force (N) =

Example: A door has its handle 70cm away from its pivot and 
the force exerted on the door is 8 (N)

Distance from Pivot (70) X Force (8) = 560 Ncm2
In the human body there are several types of pressure 
receptor. Baroreceptors monitor blood pressure in the 
carotid arteries, aortic arch and right atrium of the 
heart. Mechanoreceptors are part of the somatosensory 
system and are present in the dermis of the skin and in 
deeper tissues. They respond to different forms of touch 
and pressure; the main types of mechanoreceptor are 
Pacinian corpuscles, Meissner's corpuscles, Merkel cells 
and Ruffini endings.1 Pa = 1 N/m² = 10−5 bar = 10.197×10−6 
at = 9.8692×10−6 atm ....etc.
Note: mmHg is an abbreviation for millimetres of mercury.

The SI unit for pressure is the pascal (Pa), equal to one 
newton per square metre (N·m-2 or kg·m-1·s-2). This special 
name for the unit was added in 1971; before that, pressure 
in SI was expressed in units such as N/m².

Non-SI measures (still in use in some parts of the world) 
include the pound-force per square inch (psi) and the bar.

The cgs unit of pressure is the barye (ba). It is equal to 
1 dyn·cm-2.

Pressure is still sometimes expressed in kgf/cm² or grams-
force/cm² (sometimes as kg/cm² and g/cm² without properly 
identifying the force units). But using the names kilogram, 
gram, kilogram-force, or gram-force (or their symbols) as a 
unit of force is expressly forbidden in SI; the unit of 
force in SI is the newton (N). The technical atmosphere 
(symbol: at) is 1 kgf/cm².

Some meteorologists prefer the hectopascal (hPa) for 
atmospheric air pressure, which is equivalent to the older 
unit millibar (mbar). Similar pressures are given in 
kilopascals (kPa) in practically all other fields, where 
the hecto prefix is hardly ever used. In Canadian weather 
reports, the normal unit is kPa. The obsolete unit inch of 
mercury (inHg, see below) is still sometimes used in the 
United States.

The standard atmosphere (atm) is an established constant. 
It is approximately equal to typical air pressure at earth 
mean sea level and is defined as follows.

standard atmosphere = 101325 Pa = 101.325 kPa = 1013.25 
hPa. 
Because pressure is commonly measured by its ability to 
displace a column of liquid in a manometer, pressures are 
often expressed as a depth of a particular fluid (e.g. 
inches of water). The most common choices are mercury (Hg) 
and water; water is nontoxic and readily available, while 
mercury's density allows for a shorter column (and so a 
smaller manometer) to measure a given pressure. The press 
exerted by a column of liquid of height h and density ρ is 
given by the hydrostatic pressure equation as above: p = 
hgρ.

Fluid density and local gravity can vary from one reading 
to another depending on local factors, so the height of a 
fluid column does not define pressure precisely. 
When 'millimetres of mercury' or 'inches of mercury' are 
quoted today, these units are not based on a physical 
column of mercury; rather, they have been given precise 
definitions that can be expressed in terms of SI units. The 
water-based units still depend on the density of water, a 
measured, rather than defined, quantity.

Although no longer favoured in physics, these manometric 
units are still encountered in many fields. Blood pressure 
is measured in millimetres of mercury in most of the world, 
and lung pressures in centimeters of water are still 
common. Natural gas pipeline pressures are measured in 
inches of water, expressed as '"WC' ('Water Column'). Scuba 
divers often use a manometric rule of thumb: the pressure 
exerted by ten metres depth of water is approximately equal 
to one atmosphere.

Non-SI units presently or formerly in use include the 
following:

atmosphere. 
manometric units: 
centimetre, inch, and millimetre of mercury (Torr). 
millimetre, centimetre, metre, inch, and foot of water. 
imperial units: 
kip, ton-force (short), ton-force (long), pound-force, 
ounce-force, and poundal per square inch. 
pound-force, ton-force (short), and ton-force (long) per 
square foot. 
non-SI metric units: 
bar, millibar. 
kilogram-force, or kilopond, per square centimetre 
(technical atmosphere). 
gram-force and tonne-force (metric ton-force) per square 
centimetre. 
barye (dyne per square centimetre). 
kilogram-force and tonne-force per square metre. 
sthene per square metre (pieze). Stagnation pressure is the 
pressure a fluid exerts when it is forced to stop moving. 
Consequently, although a fluid moving at higher speed will 
have a lower static pressure, it may have a higher 
stagnation pressure when forced to a standstill. Static 
pressure and stagnation pressure are related by the Mach 
number of the fluid. In addition, there can be differences 
in pressure due to differences in the elevation (height) of 
the fluid. See Bernoulli's equation (note: Bernoulli's 
equation only applies for incompressible flow).

The pressure of a moving fluid can be measured using a 
Pitot probe, or one of its variations such as a Kiel probe 
or Cobra probe, connected to a manometer. Depending on 
where the inlet holes are located on the probe, it can 
measure static pressure or stagnation pressure.

Now Stress:

Stress (physics) 
A mature tree trunk may support a greater force than a fine 
steel wire but intuitively we feel that steel is stronger 
than wood. To predict the forces which a structure of any 
size, made of any material, can sustain without failing, we 
need the concept of mechanical stress.

The definition of stress originates in two observations of 
the behaviour of a one-dimensional body subject to uniaxial 
loading, for example, a steel wire under uniaxial tension:

When the wire is pulled, it stretches. Up to a certain 
load, the stretch ratio (current length / initial length) 
is proportional to the load divided by the cross-sectional 
area of the wire. We therefore define the stress as σ = 
F/A. 
Failure occurs when the load exceeds a critical value for 
the material, the tensile strength multiplied by the cross-
sectional area of the wire, Fc = σt A. 
These observations suggest that the quantity that effects 
the deformation and failure of materials is stress.

In the more general setting of continuum mechanics, stress 
is a measure of the internal distribution of force per unit 
area that balances and reacts to the external loads or 
boundary conditions applied to a body. Stress is an example 
of a type of quantity called a second-order tensor. In 3-
dimensions, a second-order tensor can be represented by a 
3x3 square matrix containing nine components. However, in 
the absence of body moments, the stress tensor is symmetric 
and can be fully specified by six components. These six 
components are sometimes written in Voigt notation as a 6x1 
column matrix which is often, misleadingly, called the 
stress vector.

In N-dimensions, the stress tensor is defined by:


where the are the components of the resultant force vector 
acting on a small area which can be represented by a vector 
perpendicular to the area element, facing outwards and with 
length equal to the area of the element. In elementary 
mechanics, the subscripts are often denoted x,y,z rather 
than 1,2,3.

In a 1-dimensional system, such as a uniaxially loaded bar, 
stress is simply equal to the applied force divided by the 
cross-sectional area of the bar (see also pressure). The 2-
D or 3-D cases are more complex. In three dimensions, the 
internal force acting on a small area dA of a plane that 
passes through a point P can be resolved into three 
components: one normal to the plane and two parallel to the 
plane (see Figure 1). The normal component divided by dA 
gives the normal stress (usually denoted σ), and the 
parallel components divided by the area dA give shear 
stresses (denoted τ in elementary textbooks). If the area 
dA is finite then, strictly, these are average stresses. In 
the limit, when dA approaches zero, the stresses become 
stresses at the point P. In general, stress varies from 
point to point and so is a tensor field.

The components of the stress tensor depend on the 
orientation of the plane that passes through the point 
under consideration, i.e on the viewpoint of the observer. 
This leads to the ridiculous conclusion that the stress on 
a structure, and hence its proximity to failure, depends on 
the viewpoint of the observer. However, every tensor, 
including stress, has invariants that don't depend on the 
choice of viewpoint. The length of a first-order tensor, 
i.e a vector, is a simple example. The existence of 
invariants means that the components seen by one observer 
are related, via the tensor transformation relations, to 
those seen by any other observer. The transformation 
relations for a second-order tensor like stress are 
different from those of a first-order tensor, which is why 
it is misleading to speak of the stress 'vector'. Mohr's 
circle method is a graphical method for performing stress 
(or strain) transformations.

Stress can be applied to all types of materials, including 
solids, liquids and gases. Static fluids can support normal 
or hydrostatic stress (pressure) but will flow under shear 
stress. Moving viscous fluids can support shear stress 
('dynamic pressure'). Solids can support both shear and 
normal stress, even when static. Brittle fracture of solids 
is controlled by the maximum principal stress, which is a 
normal stress. Ductile fracture of solids is controlled by 
the Mises stress, which depends on the shear stresses. Some 
materials are however difficult to pigeonhole and their 
reaction to stress may be rate-dependent, i.e depend on the 
speed with which the stress is applied or temperature 
dependent. Toffee, for example, is a brittle solid at room 
temperature when the stress rate is high, a ductile solid 
when the stress rate is low or the temperature is higher 
and a viscous fluid when the temperature is raised even 
more.
All real objects occupy 3-dimensional space. However, if 
two dimensions are very large or very small compared to the 
others, the object may be modelled as one-dimensional. This 
simplifies the mathematical modelling of the object. One-
dimensional objects include a piece of wire loaded at the 
ends and viewed from the side and a metal sheet loaded on 
the face and viewed up close and through the cross-section.

For 1-dimensional objects, the stress tensor has only one 
component and is indistinguishable from a scalar. The 
simplest definition of stress, σ = F/A, where A is the 
initial cross-sectional area prior to the application of 
the load, is called engineering stress or nominal stress. 
However, when any material is stretched, its cross-
sectional area reduces by an amount that depends on the 
Poisson's ratio of the material. Engineering stress 
neglects this change in area. The stress axis on a stress-
strain graph is often engineering stress, even though the 
sample may undergo a substantial change in cross-sectional 
area during testing.

True stress is an alternative definition in which the 
initial area is replaced by the current area. In 
engineering applications, the initial area is always known 
and so calculations using nominal stress are generally 
easier. For small deformation, the reduction in cross-
sectional area is small and the distinction between nominal 
and true stress is insignificant. This isn't so for the 
large deformations typical of elastomers and plastic 
materials when the change in cross-sectional areas can be 
significant.

In one dimension, true stress is related to nominal stress 
via σtrue = σ(1 + ε) where ε is nominal strain and σ is 
nominal stress. In uniaxial tension, true stress is then 
greater than the nominal stress. The converse holds in 
compression.

Example: a steel bolt of diameter 5 mm, has a cross-
sectional area of 19.6 mm2. A load of 50 N induces a stress 
(force distributed over the cross section) of σ = 50/19.6 = 
2.55 MPa (N/mm2). This can be thought of as each square 
millimeter of the bolt supporting 2.55 N of the total load. 
In another bolt with half the diameter, and hence a quarter 
the cross-sectional area, carrying the same 50 N load, the 
stress will be quadrupled (10.2 MPa).

The ultimate tensile strength is a property of a material 
and is usually determined experimentally from a uniaxial 
tensile test. It allows the calculation of the load that 
would cause fracture. The compressive strength is a similar 
property for compressive loads. The yield stress is the 
value of stress causing plastic deformation.


All real objects occupy 3-dimensional space. However, if 
one dimension is very large or very small compared to the 
others, the object may be modelled as two-dimensional. This 
simplifies the mathematical modelling of the object. Two-
dimensional objects include a piece of wire loaded on the 
sides and viewed up close and through the cross-section and 
a metal sheet loaded in-plane and viewed face-on.

Notice that the same physical, three-dimensional object can 
be modelled as one-dimensional, two-dimensional or even 
three-dimensional, depending on the loading and viewpoint 
of the observer.


Plane stress is a two-dimensional state of stress (Figure 
2). This 2-D state models well the state of stresses in a 
flat, thin plate loaded in the plane of the plate. Figure 2 
shows the stresses on the x- and y-faces of a differential 
element. Not shown in the figure are the stresses in the 
opposite faces and the external forces acting on the 
material. Since moment equilibrium of the differential 
element shows that the shear stresses on the perpendicular 
faces are equal, the 2-D state of stresses is characterized 
by three independent stress components (σx, σy, τxy). Note 
that forces perpendicular to the plane can be abbreviated. 
For example, σx is an abbreviation for σxx. This notation 
is described further below.





Cauchy was the first to demonstrate that at a given point, 
it is always possible to locate two orthogonal planes in 
which the shear stress vanishes. These planes are called 
the principal planes, while the normal stresses on these 
planes are the principal stresses. They are the eigenvalues 
of the stress tensor and are orthogonal because the stress 
tensor is symmetric (as per the spectral theorem). 
Eigenvalues are invariants with respect to choice of basis 
and are the roots of the Cayley–Hamilton theorem (although 
the term 'the' invariants usually means (I1,I2,I3)). Mohr's 
circle is a graphical method of extracting the principal 
stresses in a 2-dimensional stress state. The maximum and 
minimum principal stresses are the maximum and minimum 
possible values of the normal stresses. The maximum 
principal stress controls brittle fracture.







Engineers use Mohr's circle to find the planes of maximum 
normal and shear stresses, as well as the stresses on known 
weak planes. For example, if the material is brittle, the 
engineer might use Mohr's circle to find the maximum 
component of normal stress (tension or compression); and 
for ductile materials, the engineer might look for the 
maximum shear stress.


Augustin Louis Cauchy enunciated the principle that, within 
a body, the forces that an enclosed volume imposes on the 
remainder of the material must be in equilibrium with the 
forces upon it from the remainder of the body.

This intuition provides a route to characterizing and 
calculating complicated patterns of stress. To be exact, 
the stress at a point may be determined by considering a 
small element of the body that has an area ΔA, over which a 
force ΔF acts. By making the element infinitesimally small, 
the stress vector σ is defined as the limit:


Being a tensor, the stress has two directional components: 
one for force and one for plane orientation; in three 
dimensions these can be two forces within the plane of the 
area A, the shear components, and one force perpendicular 
to A, the normal component. Therefore the shear stress can 
be further decomposed into two orthogonal force components 
within the plane. This gives rise to three total stress 
components acting on this plane. For example in a plane 
orthogonal to the x axis, there can be a normal force 
applied in the x direction and a combination of y and z in 
plane force components.

The considerations above can be generalized to three 
dimensions. However, this is very complicated, since each 
shear loading produces shear stresses in one orientation 
and normal stresses in other orientations, and vice versa. 
Often, only certain components of stress will be important, 
depending on the material in question.

The von Mises stress is derived from the distortion energy 
theory and is a simple way to combine stresses in three 
dimensions to calculate failure criteria of ductile 
materials. In this way, the strength of material in a 3-D 
state of stress can be compared to a test sample that was 
loaded in one dimension.




Because the behavior of a body does not depend on the 
coordinates used to measure it, stress can be described by 
a tensor. In the absence of body moments, the stress tensor 
is symmetric and can always be resolved into the sum of two 
symmetric tensors:

a mean or hydrostatic stress tensor, involving only pure 
tension and compression; and 
a shear or deviatoric stress tensor, involving only shear 
stress. 
In the case of a fluid, Pascal's law shows that the 
hydrostatic stress is the same in all directions, at least 
to a first approximation, so can be captured by the scalar 
quantity pressure. Thus, in the case of a solid, the 
hydrostatic (or isostatic) pressure p is defined as one 
third of the trace of the tensor, i.e., the mean of the 
diagonal terms.



In the generalized stress tensor notation, the tensor 
components are written σij, where i and j are in {1;2;3}.

(caution: subscript notation in this section is different 
from the rest of the article - the order of subscripts is 
reversed)

The first step is to number the sides of the cube. When the 
lines are parallel to a vector base , then:

the sides perpendicular to are called j and -j; and 
from the center of the cube, points toward the j side, 
while the -j side is at the opposite. 


σij is then the component along the i axis that applies on 
the j side of the cube. (Or in books in the English 
language, σij is the stress on the i face acting in the j 
direction -- the transpose of the subscript notation 
herein. But transposing the subscript notation produces the 
same stress tensor, since a symmetric matrix is equal to 
its transpose.)



This generalized notation allows an easy writing of 
equations of the continuum mechanics, such as the 
generalized Hooke's law:


The correspondence with the former notation is thus:

x → 1 
y → 2 
z → 3 
σxx → σ11 
τxy → σ12 
τxz → σ13 
... 


The fact that the Newtonian stress is a symmetric tensor 
follows from some simple considerations. The force on a 
small volume element will be the sum of all the stress 
forces over the surface area of that element. Suppose we 
have a volume element in the form of a long bar with a 
triangular cross section, where the triangle is a right 
triangle. We can neglect the forces on the ends of the bar, 
because they are small compared to the faces of the bar. 
Let be the vector area of one face of the bar, be the area 
of the other, and be the area of the "hypotenuse face" of 
the bar. It can be seen that


Let's say is the force on area and likewise for the other 
faces. Since the stress is by definition the force per unit 
area, it is clear that


The total force on the volume element will be:


Let's suppose that the volume element contains mass, at a 
constant density. The important point is that if we make 
the volume smaller, say by halving all lengths, the area 
will decrease by a factor of four, while the volume will 
decrease by a factor of eight. As the size of the volume 
element goes to zero, the ratio of area to volume will 
become infinite. The total stress force on the element is 
proportional to its area, and so as the volume of the 
element goes to zero, the force/mass (i.e. acceleration) 
will also become infinite, unless the total force is zero. 
In other words:


This, along with the second equation above, proves that the 
σ function is a linear vector operator (i.e. a tensor). By 
an entirely analogous argument, we can show that the total 
torque on the volume element (due to stress forces) must be 
zero, and that it follows from this restriction that the 
stress tensor must be symmetric.

However, there are two fundamental ways in which this mode 
of thinking can be misleading. First, when applying this 
argument in tandem with the underlying assumption from 
continuum mechanics that the Knudsen number is strictly 
less than one, then in the limit , the symmetry assumptions 
in the stress tensor may break down. This is the case of 
Non-Newtonian fluid, and can lead to rotationally non-
invariant fluids, such as polymers. The other case is when 
the system is operating on a purely finite scale, such as 
is the case in mechanics where Finite deformation tensors 
are used.


The state of stress as defined by the stress tensor is an 
equilibrium state if the following conditions are satisfied:






σij are the components of the tensor, and f 1 , f 2 , and f 
3 are the body forces (force per unit volume).

These equations can be compactly written using Einstein 
notation in which repeated indices are summed. Defining as 
the equilibrium conditions are written:


The equilibrium conditions may be derived from the 
condition that the net force on an infinitesimal volume 
element must be zero. Consider an infinitesimal cube 
aligned with the x1, x2, and x3 axes, with one corner at xi 
and the opposite corner at xi + dxi and having each face of 
area dA. Consider just the faces of the cube which are 
perpendicular to the x1 axis. The area vector for the near 
face is [ − dA,0,0] and for the far face it is [dA,0,0]. 
The net stress force on these two opposite faces is


A similar calculation can be carried out for the other 
pairs of faces. The sum of all the stress forces on the 
infinitesimal cube will then be


Since the net force on the cube must be zero, it follows 
that this stress force must be balanced by the force per 
unit volume fi on the cube (e.g., due to gravitation, 
electromagnetic forces, etc.) which yields the equilibrium 
conditions.

Equilibrium also requires that the resultant moment on the 
cube of material must be zero. Taking the moment of the 
forces above about any suitable point, it follows that, for 
equilibrium in the absence of body moments

σij = σji. 
The stress tensor is then symmetric and the subscripts can 
be written in either order.


As with force, stress cannot be measured directly but is 
usually inferred from measurements of strain and knowledge 
of elastic properties of the material. Devices capable of 
measuring stress indirectly in this way are strain gages 
and piezoresistors.


The SI unit for stress is the pascal (symbol Pa), the same 
as that of pressure. Since the pascal is so small, 
engineering quantities are usually measured in megapascals 
(MPa) or gigapascals (GPa) In US Customary units, stress is 
expressed in pounds-force per square inch (psi). See also 
pressure.



Residual stresses are stresses that remain after the 
original cause of the stresses has been removed. Residual 
stresses occur for a variety of reasons, including 
inelastic deformations and heat treatment. Heat from 
welding may cause localized expansion. When the finished 
weldment cools, some areas cool and contract more than 
others, leaving residual stresses. Castings may also have 
large residual stresses due to uneven cooling.

While uncontrolled residual stresses are undesirable, many 
designs rely on them. For example, toughened glass and 
prestressed concrete rely on residual stress to prevent 
brittle failure. Similarly, a gradient in martensite 
formation leaves residual stress in some swords with 
particularly hard edges (notably the katana), which can 
prevent the opening of edge cracks. In certain types of gun 
barrels made with two telescoping tubes forced together, 
the inner tube is compressed while the outer tube 
stretches, preventing cracks from opening in the rifling 
when the gun is fired. These tubes are often heated or 
dunked in liquid nitrogen to aid assembly.

Press fits are the most common intentional use of residual 
stress. Automotive wheel studs, for example, are pressed 
into holes on the wheel hub. The holes are smaller than the 
studs, requiring force to drive the studs into place. The 
residual stresses fasten the parts together. Nails are 
another example.
 
Is This Answer Correct ?    0 Yes 0 No
Ishfaq
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 24
stress=load/area
pressure=force/area
 
Is This Answer Correct ?    0 Yes 0 No
Prasad Surendra Naik
 
  Re: what is the difference between stress and pressure?. what is the difference between moment and torque?
Answer
# 25
stress, internal resistance developed per unit area.
pressure, force applied per unit area.

moment, bending force* distance from it is applied.
by this bendng effect produced.
torque, twisting force * distance from it is measured.
by this shearing effect produced.
 
Is This Answer Correct ?    1 Yes 0 No
Hari Krishna
 

 
 
 
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