The operation in for-loop is "i--"..so it will print the 
decremented value first..hence the output will be:
4
3
2
1
0

sorry..please ignore the above answer..
the operation is "i--" =>post decrement,fist do the 
operation and then decrement.
so the output will be:
5

both of the answers are wrong

the correct answer is
4
3
2
1
0

All above answers are wrong.
Correct answer is 
5
3
1.
This is because the value "i" is decremented twice (once in 
the loop and second time in the printf() function).

it gives an error ,because prinf statement not given
correctly.if the printf statement is given as printf("\t%d",i--)
then the output of the prgm will be,
5 4 3 2 1 0

ur printf syntax is wrong so..u'll will get syntax error

The output for the given for loop is
5 3 1.
why because...
first the value of (i=5)>=0,so 5 is printed.After that i 
value is decremented because of i-- in the printf() and 
again i value is decremented as specified in for loop.
Now the value of i=3.
Again the loop will be continued untill the value of i 
becomes 0.

o/p will b 
4 2 0
bcoz first i=5 ok then condition after taht ok so printf 
will decrement i, so o/p 4 
then it decrement it twice for 2 times

OR 
it will give syntax error if printf(i--)is wrong

The answer given by preshit is absolutely correct...Lets 
see how ,we have >>>
for(i=5;i>=0;i--)
Now we can write this all as :
 
//start of program

STEP 1 :        for(i=5;i>=0;)
               {
STEP 2 :           prinf(i--);
STEP 3 :           i--;
             }
//end of program
 
TT :  now the loop will start with i=5 
when control reaches printf it firstly executes its 
internal statement i.e i-- and then prints i-1(i.e 4) and  
it Reduces i by 1.i becomes 3
NOW once again STEP 1 :go to TT

OUTPUT :
 4 
 2
 0

The correct answer is 

5
3
1

because

in for loop "i--" statement is there and again in printf
statement "i--" is there.

It will give compilatiin error "warning: passing argument 1
of âprintfâ makes pointer from integer without a cast",
because the syntax of printf is not right.
And it would have been printf("%d",i--);
Then correct answer is 531.


This is the correct answer rest all are wrong.[:)]

5
3
1

all the above answers are wrong i have written this program
into turbo c++ and here is what i got the output 
5
4
3
2
1
0

Here is the correct answer. I have written this program
into my program. I run it and  got the following output: 
5
4
3
2
1
0

syntax error.... in prinf...but it should be corrected then
the result will be 
5
3
1
Note ... 
in first run I=5; printf(i--) print I which is 5 and store 4
in i.
in second run i-- means 4-1=3 then printf(i--) print 3 and
store 2 in i.
in third run... i-- measn 2-1=1 then printf(i--) print 1 and
store 0 in i.
then decreament statement i-- store 1=-1 and when compare
-1>=0 become false and goto next statement after that loop.