#include<iostream.h>
#include<stdio.h>
#include<string.h>
int main()
{
char str1[100],str2[100];
int flag1=0,flag=0;
cout<<"\n\nenter 1st string:";
cin>>str1;
cout<<"\n\nenter 2nd string:";
cin>>str2;
int i=0,j=0;
for(i=0;i<strlen(str1);i++)
{ flag=0;
for(j=0;j<strlen(str2);j++)
{
if(str1[i]==str2[j])
{flag=1;
str2[j]=' ';
break;
}
}
if(flag==0)
{
flag1=1;
cout<<"\n\nnot anagrams";
break;
}
}
if(flag1!=1)
cout<<"\nanagrams";


return 0;

 }

#include<iostream.h>
#include<string.h>
int h(char letter)
{

return(letter-97);
}

int main()

{

char str1[100],str2[100];

int i=0,count[26];
for(i=0;i<26;i++)

count[i]=0;

clrscr();
cout<<"\n\nenter 1st string:";

cin>>str1;

cout<<"\n\nenter 2nd string:";

cin>>str2;
for(i=0;i<strlen(str1);i++)

{

count[h(str1[i])]++;

}
for(i=0;i<strlen(str2);i++)

{

count[h(str2[i])]--;
}      int flag=0;

for(i=0;i<26;i++)

{if(count[i]!=0)
{cout<<"\n\nnot anagrams";

flag=1;

break;

}
}

if(flag==0)

cout<<"\n\nanagrams";

return 0;

}

#include<iostream.h>
void main()
{
char a,b;
cout<<"Entr the values of a & b";
cin>>a>>b;
if(strcmp(a,b))
cout<<"Both a & b are the same";
else
cout<<"A & b are different";
}

private bool IsPartOf(string B, string A)
        {
            if(A==null || B==null) return false;
            if(B.Length>A.Length) return false;
            A = A.ToLower();
            B = B.ToUpper();

            for(int i=0; i<A.Length;i++)
            {
                if((i<B.Length)&&(A[i]==B[i]))
                {
                    bool found = true;
                    for(int j=i;j<B.Length;j++)
                    {
                        if(A[j]!=B[j])
                        {
                            found = false;
                            break;
                        }
                    }
                    if(found) return true;
                }
            }
            return false;
        }

using namespace std;
#include<iostream>
#include<conio.h>
#include<string.h>

int main()
{
char str1[10],str2[10],temp[10];
char *p,*q;
int flag=1;

cout<<"enter the two strings"<<endl;
cin>>str1;
cout<<"and"<<endl;
cin>>str2;

p=str1;

//strcpy(str2,temp);
//cout<<temp;
if(strlen(str1)!=strlen(str2))
flag=0;

while(*p)
{
char ch=*p;
q=str2;
while(*q)
{
         if(ch!=*q)
         q++;
         else
         {
             *q='*';
              break;
         } 
}
if((*q)=='\0')
{flag=0;
 break;
}
p++;

}

if(flag)
cout<<"anagrams"<<endl;
else
cout<<"not anagrams"<<endl;

getch();
return 0;
}

#include<stdio.h>
#include<string.h>

int main()
{
        char *str1 = "Hello";
        char *str2 = "Hello";

        int len1,len2;
        len1 = strlen(str1);
        len2 = strlen(str2);
        if(len1 != len2)
        {
                printf("\nBoth Strings are not matched");
                return 0;
        }

        while(*str1)
        {
                if(*str1 == *str2)
                {
                        *str1++;
                        *str2++;
                }
                else
                {
                        printf("\nString Not Matched\n");
                        return 0;
                }
        }
        printf("\nBoth String are EQual");
}

why u all waisting time... First understand problem then solve. 
Problem is like that

suppose B  = "iwantto"
        A = "Hiwannachatoopsthatiswhy"

Now here all character of B is in A string...

Okay!!!

//assuming both the strings in same case
 
int main()
{
	
	string A;
	string B;
	
	int count = 0;
	char repeatChar='$';
		
	cout<<"Enter string A";
	cin>>A;
	cout<<"Enter the string B";
	cin>>B;

	if(A.length()<B.length())
	{
		cout<<"Length of string A is small than B, so all the charaters of the B can't be there in A";
		exit(0);
	}
	
	
	int A_length = A.length();
	int B_length = B.length();
	
	for(int i=0; i<B_length; i++)
	{
		for(int j=0; j<A_length; j++)
		{
			if(A[j] == B[i])
			{
				if(repeatChar == A[j])
					;
				else
				{
					count++;
					repeatChar = A[j];
					break;
				}
				
			}
		}
	}	
		
	if(count==B_length)
		cout<<"string A has all the chars of string B";
	else
		cout<<"string A doesn't have all chars of string B";
        
        return 0;
	
}

char B_str[] = "aaaaaa";
char A_str[] = "a"
// For the above case, this function should return true

char B_str[] = "aB";
char A_str[] = "aaaaaBaaaaaa"
// For the above case, this function should return true

int B_chars[256]; //for all unique chars in B_str

/* Init B_chars[] */
for( int i = 0; i < 256; i++ )
    B_chars[i] = 0;

/* Get characters in B_str */
for( int i = 0; i < strlen(B_str); i++ )
    B_chars[(int) B_str[i]]++;

/* check if A_str has which of them */
for( int i = 0; i < strlen(A_str); i++ )
    B_chars[(int) A_str[i]] = 0;

/* If any of the B_chars[] has non-zero entry */
for( int i = 0; i < 256; i++ )
{
    if( B_chars[i] != 0 )
    {
       return (false);
    }
}

/* Otherwise return true   */
return (true);

//This works for strings of a fixed length(here 10)..Its
written in assumption that strings are given in same case
completely(ie,india,INdia will be false witout modifican..

#include<stdio.h>
#include<string.h>
main(){
  char a1[10],a2[10],cn[10]={0,0,0,0,0,0,0,0,0,0};
  int i,j,k,l,c=0;
  printf("enter string B\n");
  scanf("%s",a1);
  printf("enter string A\n");
  scanf("%s",a2);
 for(i=0;i<strlen(a1);i++){
        for(j=0;j<strlen(a2);j++){
           if(a1[i]==a2[j]){
           c++;
           cn[i]=1;
           }}}
           for(k=0;k<strlen(a1);k++){
           if(cn[k]==0){
           printf("FALSE\n");exit(0);}}
           printf("TRUE\n");}