#include<stdio.h>
#include<conio.h>
void main()
{
int num,i=2;
clrscr();
printf("\n entert a number");
scanf("%d",&num);
while(c<=num-1)
{
if(num%i==0)
{
printf("given number is not a prime number\n");
break;
}
i++;
}
if(i==num);
printf(given number is a prime number\n");
getch();
}
\*Write a program wither given number is prime or not */
\*I think it is different to others (BY ANJAN)*/
#include<stdio.h>
main()
{
int n,a=3;
printf("Enter Number");
scanf("%d",&n);
if(n==2)
{
printf("Given Number is PRIME");
exit (0);
}
if(n==3)
{
printf("Given Number is PRIME");
exit (1);
}
if(n%2==0)
{
printf("Given Number is NOT PRIME");
exit (2);
}
while(a<=n/2)
{
if(n%a==0)
{
printf("Given Number is NOT PRIME");
exit (3);
}
a=a+2;
}
printf("Given Numbr is PRIME");
}
what will be the result of the following program ?
char *gxxx()
{
static char xxx[1024];
return xxx;
}
main()
{
char *g="string";
strcpy(gxxx(),g);
g = gxxx();
strcpy(g,"oldstring");
printf("The string is :
%s",gxxx());
}
a) The string is : string
b) The string is :Oldstring
c) Run time error/Core dump
d) Syntax error during compilation
e) None of these