printf("____________________");
printf("\n|\t\t|\n|\t\t|\n|\t\t|\n|\t\t|");
printf("____________________");
by this way i think can be possible,though some
adjustment may required...as per size of VDU.As per my
opinion intervier asked for this answer....as C graphics is
not so popularly used.
Pardon me if i'm wrong & can also mail to me.
First we insert the graphics mode into your complier,and we
use the function rectangle(); in the rectangle function we
specified the length and breath,and we also specified where
the place in screen the rectangle is drawn.
#include
#include
#include
main()
{
int gd=DETECT, gm,x,y;
int arr[]={540,220,590,270,570,320,510,320,490,270,540,220};
initgraph(&gd,&gm,"c:\\tc\\bgi");
x=getmaxx();
y=getmaxy();
setcolor(GREEN);
printf(" \n value of x = %d",x);
printf(" and the value of y = %d",y);
rectangle(5,40,140,200);
outtextxy(x/30+15,y/8+5,"Rectangle");
drawpoly(6,arr);
outtextxy(515,270,"Polygon");
setcolor(RED);
line(0,49,639,479);
line(0,0,0,479);
line(0,0,639,0);
line(639,0,639,479);
getch();
closegraph();
restorecrtmode();
}
func(a,b)
int a,b;
{
return( a= (a==b) );
}
main()
{
int process(),func();
printf("The value of process is %d !\n
",process(func,3,6));
}
process(pf,val1,val2)
int (*pf) ();
int val1,val2;
{
return((*pf) (val1,val2));
}
struct point
{
int x;
int y;
};
struct point origin,*pp;
main()
{
pp=&origin;
printf("origin is(%d%d)\n",(*pp).x,(*pp).y);
printf("origin is (%d%d)\n",pp->x,pp->y);
}
main()
{
int i;
clrscr();
printf("%d", &i)+1;
scanf("%d", i)-1;
}
a. Runtime error.
b. Runtime error. Access violation.
c. Compile error. Illegal syntax
d. None of the above