this program is gonna give output 10.coz ascii values are
assigned to only 0....9.when we execute printf("%
c",ch);.........the output screen will be blank.
@Devvvv
every character has an ascii value..
it is not that only 0 - 9 has ascii values.. even 10 , 20
has ascii values.
each and every value has an ascii value..
comming back to the ques:
i think it will give the ascii value of 10...
The output will be 10.
char consists of 1 byte = 8 bits
it can hold any value between 0 - 127
an unsigned char can hold any 0 - 256
the asci value 10 is newline,
so if u format it as char using %c
printf ( "\n|%c|", ch ); the 10 is converted to new line
otherwise if u format it to int using %d, it ud print 10
What is the function of ceil(X) defined in math.h do?
A)It returns the value rounded down to the next lower
integer
B)it returns the value rounded up to the next higher integer
C)the Next Higher Value
D)the next lower value
what is the output of the following program?
main()
{
int c[]={2,8,3,4,4,6,7,5};
int j,*p=c,*q=c;
for(j=0;j<5;j++)
{
printf("%d",*c);
++q;
}
for(j=0;j<5;j++)
{
printf("%d",*p);
++p;
}
}
Write one statement equalent to the following two statements
x=sqr(a);
return(x);
Choose from one of the alternatives
a.return(sqr(a));
b.printf("sqr(a)");
c.return(a*a*a);
d.printf("%d",sqr(a));
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