String is an immutable object.
Then how can the following code be justified.
String s1 = ?ABC?;
String s1 = s1+?XYZ?;
s.o.p(s1);
The output is ABCXYZ, which is the value of s1 ?
Re: String is an immutable object.
Then how can the following code be justified.
String s1 = ?ABC?;
String s1 = s1+?XYZ?;
s.o.p(s1);
The output is ABCXYZ, which is the value of s1 ?
in the later case a different overloaded contructor is
invoked while in the prior case a different.As in the later
case a different constructor initializes the string s1 with
different values hence the result
Re: String is an immutable object.
Then how can the following code be justified.
String s1 = ?ABC?;
String s1 = s1+?XYZ?;
s.o.p(s1);
The output is ABCXYZ, which is the value of s1 ?
here we define s1="ABC".That means one new string is
created.And this string value is stored in heap its
refrence variable is s1.when we say s1+"XYZ".Then string s1
i.e ABC and XYZ are concadinated by using concadination
operater.It forms a new string i.e "ABCXYZ" in heap.But
again we assign this value to the refrence variable
s1.Then "ABCXYZ" value is assign to s1 and the string "ABC"
which is garbage collected.
Re: String is an immutable object.
Then how can the following code be justified.
String s1 = ?ABC?;
String s1 = s1+?XYZ?;
s.o.p(s1);
The output is ABCXYZ, which is the value of s1 ?
Re: String is an immutable object.
Then how can the following code be justified.
String s1 = ?ABC?;
String s1 = s1+?XYZ?;
s.o.p(s1);
The output is ABCXYZ, which is the value of s1 ?
above program is incorrect ,it will give compile time error
as "Duplicate Variable s1".
it should b
String s1 = "ABC";
String s = s1+"XYZ";
which is valid in string ,as we are creating new String
object
Re: String is an immutable object.
Then how can the following code be justified.
String s1 = ?ABC?;
String s1 = s1+?XYZ?;
s.o.p(s1);
The output is ABCXYZ, which is the value of s1 ?
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