Consider the following algorithm, where the array A is indexed 1 through n:
int add_them ( int n , int A[ ] ) {
index i , j , k ;
j = 0 ;
for ( i = 1 ; i <= n ; i++)
j = j + A[i] ;
k = 1 ;
for ( i = 1 ; i <= n ; i++)
k = k + k ;
return j + k ;
}
(a) If n = 5 and the array A contains 2, 5, 3, 7, and 8, what is returned?
(b) What is the time complexity T(n) of the algorithm?
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Consider the following algorithm: j = 1 ; while ( j <= n/2) { i = 1 ; while ( i <= j ) { cout << j << i ; i++; } j++; } (a) What is the output when n = 6, n = 8, and n = 10? (b) What is the time complexity T(n)? You may assume that the input n is divisible by 2.
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