Exp:-length of wall=10ft
Bredth of wall=4.5in
Height of wall=9.5ft
Qty.10*0.375*9.5=35.625cft
Provide .5in morter in each line of bricks.
So,first calculate qty.of mortar in total work with following steps:-
Step-1. Calcuate qty. of mortar in one line
of bricks:-
10*0.375*0.0625=0.2344cft.
Step-2. Calculate nos. of lines of bricks in given height:-
9.5/0.292=32.53 or 33bricks.
Step-3. Calculate qty. of mortar:-
33*0.2344=7.73cft.
So,Total brick work:-
35.625-7.73=27.895cft
Net. Qty. of bricks=
27.895/0.0703=396.8bricks
say 397 bricks

#Bricks of class designation 7.5 in foundation and plinth
in :-
Brick with wastage = 494
Mortar = .25
Cement Ratio is 1:6, then
Cement=(.25/(1+6))*1 = .0357 cum
Cement in Bags = .0357/.034722 = 1.0286 bags

Sand = (.25/(1+6))*6 = 0.2143 cum
= 0.2143 * 35.29 = 7.56 Cft
# Bricks of class designation 7.5 in superstructure above
plinth level up to floor V level in all shapes and sizes
in:-
Brick with wastage = 494
Mortar = .22
Cement Ratio is 1:6, then
Cement=(.22/(1+6))*1 = .03143 cum
Cement in Bags = .03143/.034722 = 0.905 bags

#Bricks of class designation 7.5 in foundation and plinth
in :-
Brick with wastage = 494
Mortar = .25
Cement Ratio is 1:6, then
Cement=(.25/(1+6))*1 = .0357 cum
Cement in Bags = .0357/.034722 = 1.0286 bags

Sand = (.25/(1+6))*6 = 0.2143 cum
= 0.2143 * 35.29 = 7.56 Cft
# Bricks of class designation 7.5 in superstructure above
plinth level up to floor V level in all shapes and sizes
in:-
Brick with wastage = 494
Mortar = .22
Cement Ratio is 1:6, then
Cement=(.22/(1+6))*1 = .03143 cum
Cement in Bags = .03143/.034722 = 0.905 bags

As per thumb rule cement required per 1 cum of M20 concrete
is 411Kg/cum(1.57/5.5=0.285cum of cement i.e
0.285*1440=411Kg).But as per PWD rate analysis cement
required is 347Kg/cum.the difference is 64Kg.This kind of
difference is coming every grade of concrete.Can you give
perfect suggestion regarding this.

1) what is the use of pin and plate vibrators during slab
casting? 2) how much cement bags are required for 1sqm
4inch brick wall? 3) Is it viable to provide overlap at
column , beam & slab junction. if no why? 4) if bar dia is
changing in column reinforcement , which dia bars overlap
is considered? 5) what is isolated and ecentric footing?

ground floor columns and beams are reinforced by 4 Num's 16MM @ Corners AND 2 Num's 10MM @ centre.... And the nxt top floor columns and beams were lapped by 8 num's 12MM dia bars.....
IS THIS CORRECT ????