#Bricks of class designation 7.5 in foundation and plinth
in :-
Brick with wastage = 494
Mortar = .25
Cement Ratio is 1:6, then
Cement=(.25/(1+6))*1 = .0357 cum
Cement in Bags = .0357/.034722 = 1.0286 bags

Sand = (.25/(1+6))*6 = 0.2143 cum
= 0.2143 * 35.29 = 7.56 Cft
# Bricks of class designation 7.5 in superstructure above
plinth level up to floor V level in all shapes and sizes
in:-
Brick with wastage = 494
Mortar = .22
Cement Ratio is 1:6, then
Cement=(.22/(1+6))*1 = .03143 cum
Cement in Bags = .03143/.034722 = 0.905 bags

Exp:-length of wall=10ft
Bredth of wall=4.5in
Height of wall=9.5ft
Qty.10*0.375*9.5=35.625cft
Provide .5in morter in each line of bricks.
So,first calculate qty.of mortar in total work with following steps:-
Step-1. Calcuate qty. of mortar in one line
of bricks:-
10*0.375*0.0625=0.2344cft.
Step-2. Calculate nos. of lines of bricks in given height:-
9.5/0.292=32.53 or 33bricks.
Step-3. Calculate qty. of mortar:-
33*0.2344=7.73cft.
So,Total brick work:-
35.625-7.73=27.895cft
Net. Qty. of bricks=
27.895/0.0703=396.8bricks
say 397 bricks

#Bricks of class designation 7.5 in foundation and plinth
in :-
Brick with wastage = 494
Mortar = .25
Cement Ratio is 1:6, then
Cement=(.25/(1+6))*1 = .0357 cum
Cement in Bags = .0357/.034722 = 1.0286 bags

Sand = (.25/(1+6))*6 = 0.2143 cum
= 0.2143 * 35.29 = 7.56 Cft
# Bricks of class designation 7.5 in superstructure above
plinth level up to floor V level in all shapes and sizes
in:-
Brick with wastage = 494
Mortar = .22
Cement Ratio is 1:6, then
Cement=(.22/(1+6))*1 = .03143 cum
Cement in Bags = .03143/.034722 = 0.905 bags

Providing cement based water proofing treatment to terrace
(Indian water proofing) with brick bats with cement morter
(1:5) and (1:3).
what are rate in cum or sqm.