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Question
1 Cum  Brick Work CM 1: 6 - How Many Bricks ,sand,Cement
Required? Brick Size 9" 4.5" 3"
 Question Submitted By :: Civil-Engineering
I also faced this Question!!     Answer Posted By  
 
Answer
# 1
Volume of 1 Brick = 0.230*0.115*0.075 = 0.002
So No of brick req for 1 m3 = (1/0.002) = 500 Nos

1.7 bag of Cement required

0.31 cum sand required for 1 cum of brickwork
 
Is This Answer Correct ?    74 Yes 16 No
Hussain
 
Answer
# 2
brick size in meter=.23*.115*.075 =.0019
add 10 mm mortar for ech sides=(.24*.125*.085)=(.0025)

bricks required for 1 m3 =(1/(0.0025)=400 nos

mortar required =(.0025-.0019)*400=.24

add 15% for wastage = (.24*1.15)=.276m3

so required sand is =.276 m3

cement is =(1440/6)=240*.276= 66 kg
 
Is This Answer Correct ?    25 Yes 14 No
Raja J
 
 
 
Answer
# 3
Bricks :395
Cement:1.25 Bags (CPWD)
C-sand:10 cft
 
Is This Answer Correct ?    9 Yes 4 No
Md.furqan Anasri
 
Answer
# 4
Sorry For above Answer

By Analysis of Rate-2007

#Bricks of class designation 7.5 in foundation and plinth
in :-
Brick with wastage = 494
Mortar = .25
Cement Ratio is 1:6, then
Cement=(.25/(1+6))*1 = .0357 cum
Cement in Bags = .0357/.034722 = 1.0286 bags

Sand = (.25/(1+6))*6 = 0.2143 cum
= 0.2143 * 35.29 = 7.56 Cft
# Bricks of class designation 7.5 in superstructure above
plinth level up to floor V level in all shapes and sizes
in:-
Brick with wastage = 494
Mortar = .22
Cement Ratio is 1:6, then
Cement=(.22/(1+6))*1 = .03143 cum
Cement in Bags = .03143/.034722 = 0.905 bags

Sand = (.22/(1+6))*6 = 0.189cum
= 0.189* 35.29 = 6.655 Cft
 
Is This Answer Correct ?    11 Yes 9 No
Md Gyasuddin Ahsan
 
Answer
# 5
500 bricks, 
Is This Answer Correct ?    2 Yes 0 No
Guest
 
Answer
# 6
Exp:-length of wall=10ft
Bredth of wall=4.5in
Height of wall=9.5ft
Qty.10*0.375*9.5=35.625cft
Provide .5in morter in each line of bricks.
So,first calculate qty.of mortar in total work with following steps:-
Step-1. Calcuate qty. of mortar in one line
of bricks:-
10*0.375*0.0625=0.2344cft.
Step-2. Calculate nos. of lines of bricks in given height:-
9.5/0.292=32.53 or 33bricks.
Step-3. Calculate qty. of mortar:-
33*0.2344=7.73cft.
So,Total brick work:-
35.625-7.73=27.895cft
Net. Qty. of bricks=
27.895/0.0703=396.8bricks
say 397 bricks
 
Is This Answer Correct ?    2 Yes 0 No
Er.harjinder Singh
 
Answer
# 7
By Analysis of Rate-2007

#Bricks of class designation 7.5 in foundation and plinth
in :-
Brick with wastage = 494
Mortar = .25
Cement Ratio is 1:6, then
Cement=(.25/(1+6))*1 = .0357 cum
Cement in Bags = .0357/.034722 = 1.0286 bags

Sand = (.25/(1+6))*6 = 0.2143 cum
= 0.2143 * 35.29 = 7.56 Cft
# Bricks of class designation 7.5 in superstructure above
plinth level up to floor V level in all shapes and sizes
in:-
Brick with wastage = 494
Mortar = .22
Cement Ratio is 1:6, then
Cement=(.22/(1+6))*1 = .03143 cum
Cement in Bags = .03143/.034722 = 0.905 bags

Sand = (.22/(1+6))*6 = 0.189cum
= 0.189* 35.29 = 6.655 Cft
 
Is This Answer Correct ?    1 Yes 0 No
Shahvez
 
Answer
# 8
540 bricks
1.40 cement
0.30 cu sand
 
Is This Answer Correct ?    1 Yes 1 No
Fezan Butt
 
Answer
# 9
bricks 500
cement 1.54 bags
sand .32 m^3
for C:S 1:6 brick work
 
Is This Answer Correct ?    1 Yes 1 No
Rizwan Akbar
 
Answer
# 10
cement = 1.40 Bags
sand = 10.50 Cft
Bricks = 466 Nos
 
Is This Answer Correct ?    0 Yes 1 No
Asmar Ahmed
 

 
 
 
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