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Categories  >>  Software  >>  Programming Languages  >>  C++  >>  C++ General
 
 


 

 
 STL interview questions  STL Interview Questions
 OOPS interview questions  OOPS Interview Questions
 C++ General interview questions  C++ General Interview Questions
Question
1)#include <iostream.h>

int main()
{
int *a, *savea, i;

savea = a = (int *) malloc(4 * sizeof(int));

for (i=0; i<4; i++) *a++ = 10 * i;


for (i=0; i<4; i++) {
printf("%d\n", *savea);
savea += sizeof(int);
}
return 0;
}
2)#include <iostream.h>

int main()
{
int *a, *savea, i;

savea = a = (int *) malloc(4 * sizeof(int));

for (i=0; i<4; i++) *a++ = 10 * i;


for (i=0; i<4; i++) {
printf("%d\n", *savea);
savea ++;
}
return 0;
}
The output of this two programs will be different why?
 Question Submitted By :: Santhoo035
I also faced this Question!!     Rank Answer Posted By  
 
  Re: 1)#include <iostream.h> int main() { int *a, *savea, i; savea = a = (int *) malloc(4 * sizeof(int)); for (i=0; i<4; i++) *a++ = 10 * i; for (i=0; i<4; i++) { printf("%d\n", *savea); savea += sizeof(int); } return 0; } 2)#include <iostream.h> int main() { int *a, *savea, i; savea = a = (int *) malloc(4 * sizeof(int)); for (i=0; i<4; i++) *a++ = 10 * i; for (i=0; i<4; i++) { printf("%d\n", *savea); savea ++; } return 0; } The output of this two programs will be different why?
Answer
# 1
first program prints sum of saved and size of int

second one prints only the contenst of saved
 
Is This Answer Correct ?    0 Yes 0 No
Mahesh
 
  Re: 1)#include <iostream.h> int main() { int *a, *savea, i; savea = a = (int *) malloc(4 * sizeof(int)); for (i=0; i<4; i++) *a++ = 10 * i; for (i=0; i<4; i++) { printf("%d\n", *savea); savea += sizeof(int); } return 0; } 2)#include <iostream.h> int main() { int *a, *savea, i; savea = a = (int *) malloc(4 * sizeof(int)); for (i=0; i<4; i++) *a++ = 10 * i; for (i=0; i<4; i++) { printf("%d\n", *savea); savea ++; } return 0; } The output of this two programs will be different why?
Answer
# 2
The output differs due to the followinf two statements

savea+=sizeof(int)
and
savea++

savea++
=>savea=savea+1
=>savea=savea+1*(sizeof(int))


savea+=sizeof(int)
=>savea=savea+2
=>savea=savea+2*sizeof(int)

sizeof(int) is called the scalefactor of savea
 
Is This Answer Correct ?    0 Yes 0 No
Uma Sankar Pradhan
 
 
 

 
 
 
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