Hi this is Anuj . I selected in Cmc through this  placement paper .

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Some of the Technical questions i remember are :

1.Unix OS is a 
a) multi-taks b) mutual task c)multiple processe d)a&c

2The TV Satilite Transmission is a
 a) Half-Duplex b) Full Duplex c) one-way duplex d)non of the above    
   
3Which among is the OOPL
 a) c  b) java  c) Cobol  d) PAscal

4what will be the output of
main()
{
int a=5,c;
int ptr;
ptr=&a;
c=*ptr * a;
printf("%d,%d",c,a);
}
a) 5,5     b)25,25      c) 25,5      d) Error

5.What can a Friend Keywoard do?
a) Free the memory
b) provide access to private & public variables
c) provide access to Private ,Protected, public variables.
d) never allowed to acccess any constructor

6.Abstract Class can be
a) Accessed as Constructors
b) used for hiding information of class
c) class is Abstract class
d) none of the above

7.The present LAn-card Supports
a)32kbphs     b) 64kbphs    c)128kbphs    d) 256kbphs   
                 
8.What is CDMA Technology ?
a) Electronic calculator
b) Cellular phones
c) Rocket
d) Car

9.What is GC in JAVA?
a) De-allocates the memory
b) De-allocates the objects & its reference
c) Finalising of Memory
d) non-of the above

10 which among is thread class?
a) sleep()
b) IsAliva()
c) IsLive()
d) none of the above

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11)    main()
{
int x=10,y=5,p,q;
p=x>9;
q=x>3&&y!=3;
printf("p=%d q=%
d",p,q);                                                    
}
ans:1,1.

12.main()
{
int x=11,y=6,z;
z=x==5 || !=4;
printf("z=%d",z);
}
ans:1

13)main()
{
int c=0,d=5,e=10,a;
a=c>1?d>1||e>1?100:200:300;
printf("a=%d",a);
}
ans:300

14)main()
{
int i=-5,j=-2;
junk(i,&j);
printf("i=%d,j=%d",i,j);
}
junk(i,j)
int i,*j
{
i=i*i;
*j=*j**j;
}
ans:-5,4;

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15.#define NO
#define 
YES                                                                        
main()
{
int i=5,j;
if(i>5)
j=YES;
else
j=NO;
printf("%d",j);
}
ans:Error message

16.main()
{
int a=0xff;
if(a<<4>>12)
printf("leftist)
else
printf("rightist")
}
ans:rightist

17.main() 
{
int i=+1;
while(~i)
printf("vicious 
circles")                                                       
}
ans:continuous loop.

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