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Question
```What is the power ratio between power in Star and Delta
circuit?```
Question Submitted By :: Electrical-Engineering
I also faced this Question!!     Answer Posted By

# 1
in star connection
line voltage is=(3)^(1/2)*phasevoltage
line current is=phase current
in delta connection
line voltage is =phase voltage
line current is =(3)^(1/2)*phase current

power ratio=( ((3)^(1/2)*phasevoltage*phase current)/((((3)^
(1/2)*phasevoltage*phase current))
so power ratio is =1.

 Is This Answer Correct ? 56 Yes 21 No
Karthick

# 2
the ratio of power in star & delta is 1:3
 Is This Answer Correct ? 15 Yes 5 No
Ganeshagraja Samanta

# 3
Power ratio between star and delta is 1:1
because power in star=line voltage(3^1/2*Vph)*line current
(Iph)=3^1/2VphIph
power in delta =line voltage(Vph)*line current(3^1/2*Iph)
=3^1/2VphIph

 Is This Answer Correct ? 21 Yes 12 No
Ganesh

# 4
power = 3vicos

in delta Iphase = Iline/rt3.
Vphase = Vline

ie in delta connected ckt P= rt3VphaseIphasecos

IIly in star connected vphase=Vline/rt3,
Iline=Iphase
ie Power = rt3 vpahseIphaseCos
ie. in both star and delta power remain same
therefore the Power ratio = 1.

 Is This Answer Correct ? 25 Yes 21 No

# 5
power ratio b/w star and delta is 1/3.In star, total power
will be 1/3 times of delta total power.

 Is This Answer Correct ? 12 Yes 8 No
Jothi Mahalingam

# 6
i think transformer just step up or step down voltage or
current only but power remains same(constant).so ratio of
p1 to p2 is 1 when same transformer connected in star or
delta.

 Is This Answer Correct ? 12 Yes 9 No
Alpesh Surat

# 7
The power transformation ratio in the transformer is
1:1.Only the voltage and currents are subjected to
change.Pri MVA=Secondary MVA. Except to compensate for some
losses.

 Is This Answer Correct ? 11 Yes 9 No
Reshi

# 8
If placing 3 resistors in Delta rather than Star will end
up with 3 times more heating power. This is because you
have sq root of 3 times more voltage across each resistor
in Delta and hence end up with the sq root of 3 times more
current through each resistor. The sq root of 3 of more
voltage times the sq root of 3 of more current than, star
connected resistors means 3 times more power. Capacitor
are often connected in Delta for power factor correction as
this offers 3 times more reactive power than in Star
connection, though be aware they need to be able to cope
with line voltage across each Cap in Delta.

 Is This Answer Correct ? 6 Yes 4 No
Karl

# 9
If placing 3 resistors in Delta rather than Star will end
up with 3 times more heating power. This is because you
have sq root of 3 times more voltage across each resistor
in Delta and hence end up with the sq root of 3 times more
current through each resistor. The sq root of 3 of more
voltage times the sq root of 3 of more current than, star
connected resistors means 3 times more power. Capacitor
are often connected in Delta for power factor correction as
this offers 3 times more reactive power than in Star
connection, though be aware they need to be able to cope
with line voltage across each Cap in Delta.
Thanks

 Is This Answer Correct ? 7 Yes 6 No
Pratik Chhatbar

# 10
The power ratio between Star to Delta is 1:3

Here is the Explanation:

Let?s suppose Vs be the supply voltage per phase.

So the line voltage of the supply will be ?3Vs.

Now assume any type of load; for simplicity assume it a

And let it be ?R? per phase.

Calculation for per phase power; PD= I2R

Where I ? load current (per phase)

And,

I = ?3Vs/R {as line voltage of the supply is directly
applied to the phase of the delta load}

So,

Pd = (?3Vs/R )2R = 3Vs2/R watts per phase.

For 3 phases:

P3D = 3Pd = 3*3Vs2/R = 9Vs2/R watts.

PS = I2R = (Vs/R)2R = Vs2/R watts

For 3 phases: P3S = 3PS = 3 Vs2/R watts

Conclusion:

P3S / P3D = 3Vs2/R / 9Vs2/R = 1/.

 Is This Answer Correct ? 25 Yes 57 No
Baswaraj

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