#include<iiostream.h>
class overload
{
public:
int max(int,int);
floatmax(float,float);
};
int overload::max(int num1,int num2)
{
if(num1>nmu2)
{
return num1;
}
else
{
return num2;
}
}
float overload::max(float num1,float num2)
{
if(num1>num2)
{
return num1;
}
else
{
return num2;
}
}
int main(90
{
overload o1;
cout<<"o1.max(5.4f,8.6f)<<endl;
cout<<"o1.max(19,34)<<endl;
}

8.6 for float
34 for int

FYI

for overloading a function differing only by return type is 
illegal (it is legal to use different a return type with a 
different argument list, though) :

Program illustrating function overloading

# include<iostream.h>
# include<conio.h>
int area(int side)
{
	return side*side;
}
int area(int l , int b)
{
	return l*b;
}

void main()
{
clrscr();
int (*p1)(int);
int (*p2)(int,int);

p1=area;
p2=area;

cout<<"Address of area(int)="<<(unsigned int)p1<<endl;
cout<<"Address of area(int,int)="<<(unsigned int)p2<<endl;

cout<<"Invoking area(int) via p1 "<<p1(20)<<endl;
cout<<"Invoking area(int,int) via p2 "<<p2(10,20);
getch();
}