How to count occurrences of each duplicate element in a list
{a,b,d,c,a,b} ?

Thanks in Advance

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How to count occurrences of each duplicate element in a list {a,b,d,c,a,b} ? Thanks in Advance..

Answer / lal ajith kumara

Since java.Util.Set is not allowing duplicates u can use it

String[] letters = {"a", "b", "b", "c" ,"a", "d","a"};
Set duplicateTester = new HashSet<String>();
for(int i = 0; i<letters.length;i++){
if(true == duplicateTester.add(letters[i])){
System.out.println("true>>"+letters[i]);

}else{
System.out.println("false>>"+letters[i]);
}

}

Is This Answer Correct ?    7 Yes 1 No

How to count occurrences of each duplicate element in a list {a,b,d,c,a,b} ? Thanks in Advance..

Answer / pratiksha

import java.util.*;
class alpha
{
String let;
public alpha(String l)
{
this.let=l;
}
}

public class Duplicateletters
{
public static void main(String []args)
{
int i=0;
String[] letters = {"a", "b", "b", "c" ,"a", "d","a"};
ArrayList<alpha> a = new ArrayList<alpha>();
for(i=0;i<letters.length;i++)
{
a.add(new alpha(letters[i]));
}
String let1=null;
Iterator<alpha> i1 = a.iterator();
while(i1.hasNext())
{
alpha a1 = i1.next();
let1=a1.let;
}
int j=0;
Iterator<alpha> i2 = a.iterator();
while(i2.hasNext())
{

alpha a2 = i2.next();
if(let1==a2.let)
{
j=j+1;
}
}
System.out.println(j);

}
}

Is This Answer Correct ?    3 Yes 1 No

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