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Question
how much cement,sand,aggregate will use for 1 cum in ratio of 
1:2:4.
 Question Submitted By :: Civil-Engineering
I also faced this Question!!     Answer Posted By  
 
Answer
# 1
Ratio of concrete mix =1:2:4 (Calculation for 1cum)
Cement:-
1/7*1.54=.22 cum [1.54for dry volume]
=.22/0.0345
=6.38bags
Sand:-
2/7*.22=0.06cum
=0.06*35.32
=2.12cft
Aggregate:-
4/7*.22=0.13cum
=0.13*35.32
=4.59cft
 
Is This Answer Correct ?    27 Yes 6 No
Roys
 
Answer
# 2
need anwer 
Is This Answer Correct ?    31 Yes 11 No
Nooorulhaq
 
 
 
Answer
# 3
as per is 6.4 bags of cement & 0.86m3 / 30.31cft of 20mm
aggregate & 0.46m3 / 16.25cft of sand requires for 1m3 of
m15 concrete or 1:2:4
 
Is This Answer Correct ?    31 Yes 14 No
Mr. B.nagaraj
 
Answer
# 4
R.C.C Ratio 1:2:4
0.92/4 x 28.80 = 6.624m3
wt of cement bag/m3 x 0.03472
1 x 0.0229 m3 cement
2 x 0.458 m3 Sand
4 x 0.916 m3 Concrete

50 x 0.0229 / 0.03472 = 329/50kg

6.59 No of Bag's
 
Is This Answer Correct ?    23 Yes 7 No
Mukarram
 
Answer
# 5
v=1c*2s*4G (1+2+4)=7
so for 1 cu m3 1/7= 0.15

the unit weigh of cement =1400 kg/m3
hence for
cement 0.15*1400 =210 kg
sand 2*0.15=0.3 m3
Gravel 4*.15 =0.16 m3
 
Is This Answer Correct ?    12 Yes 9 No
Huner
 
Answer
# 6
6.22 BAG OF CEMENT IN ONE CUBIC METER

.44 CUM FINE AGGREGATES

.88 CUM COARSE AGGREGATES
 
Is This Answer Correct ?    7 Yes 4 No
Javed Ashraf
 
Answer
# 7
The Ratio is 1:2:4 Total = 7

Ingredients of this Mixture is = 1.57

So the qty of Cement is = (1/7) x 1.57 = 0.224 cum

Volume of cement in i cum = 1440kg

therefore required cement = 1440 x 0.224 = 322.56kg

Weight of 1 cement bag is = 50 kg

so 322.56/50 = 6.45Bag

Add 5% for wastage = 6.45 x (5/100) = 6.77 bag required

Qty of Sand = (2/7) x 1.57 = 0.448 cum (1cum = 35.31 cuft)

convert cum to cuft = 0.448*35.31 = 15.18 cuft

Sand is available in unit,so 1 unit = 100 cuft

So required qty of sand is = 15.18/100 = 0.151 unit require

Qty of Aggregate = (4/7) x 1.57 = 0.89cum

Convert cum to cuft = 0.89 * 35.31 = 31.42cuft

sand & Aggregate also available in unit

so above the same as aggregate = 31.42/100 = 0.314 unit require
 
Is This Answer Correct ?    3 Yes 0 No
Lakshmanarajan
 
Answer
# 8
RCC 1:2:4 -density of cement=1440kg/m3 1m3 =1440/2=720*0.45
=324kg
=324/50=6.48bags
Sand=6.48*1.25
=8.0125cum
=2*8.0125
=16.025cum
Aggregate
=4*8.012
=32.05cum.
 
Is This Answer Correct ?    1 Yes 0 No
Prabakar
 
Answer
# 9
practically Material Consumption in M15 1:2:4

Quantity-1 cum

Cement beg - 6 Nos(0.198 cum)

Coarse Sand - 0.396 Cum

Coarse Aggregate 0.792 Cum
 
Is This Answer Correct ?    0 Yes 0 No
Er. Syed Layaq Ali
 
Answer
# 10
m15 1:2:4 (7 parts)
cement 1/7 x 1.57 = 0.225
Sand 2/7 x 1.57 = 0.45
Jelly 4/7 x 1.57 = 0.90

Cement : 0.225 x1440 = 324kg
Total nos of bag of cement : 324/50 = 6.48 Bags of cement
 
Is This Answer Correct ?    0 Yes 0 No
Seduraman
 

 
 
 
Other Civil Engineering Interview Questions
 
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say you are requsituoning cement to build masonry wall made of burnt clay bricks. how many 50 kgs cement bags will you requisition for 1:5 ratio mortar joint, if they masonry wall volume is 10 m3   1
how to calculate concrete quantity from its density or details mentioned in rmc batch report.   1
3,6,13,26,33,66,____   7
What is the Maximum & Minimum size of rod using on the column?   5
what is the load capacity of bored pile pile dia 500mm   1
plz send me civil q papers of hpcl Shell 4
Which IS Codes used for the steel reinforcement work?   11
what is mean by Face bar using in coloums?   1
what is the diff between sudden loading and impact loading?   3
how to find out the quantity of cement sand and aggregate in slab and flooring L&T 1
why we use min. 12mm dia bar in a coloum. BPCL-Bharat-Petroleum 6
 
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