a)If column dimensions are 250*400mm , what will be
cutting length for 8mm stirrups and how to calculate it? b)
If beam dimensions are 200*400mm , beam coveris 25mm , slab
cover is 20mm , what will be the cutting length for
stirrups? c)Column dimensions are 250*400mm , reinf. is
12nos. bar of 16mm dia , stirrups provided are two legged,
what will be the length of each ring?
Regards

1) let cover for column be 40mm (as u have not mentioned)
formula to determine cutting length of stirrup is given below
cutting length= (2A+2B)+(24D)
A=LONGER LENGTH OF COLUMN-2XCOVER=400-40X2=320MM
B=SHORTER LENGTH OF COLUMN-2XCOVER=250-40X2=170MM
D= DIAMETER OF STIRRUP BAR IN MM
therefore
cutting length=2X320+2X170 + 24X8 =1172MM=1.172 meter
2) given cover 25mm (as u have mentioned)
formula to determine cutting length of stirrup is given below
cutting length= (2A+2B)+(24D)
A=LONGER LENGTH OF BEAM-2XCOVER=400-25X2=350MM
B=SHORTER LENGTH OF BEAM-2XCOVER=200-25X2=150MM
D= DIAMETER OF STIRRUP BAR IN MM
therefore
cutting length=2X350+2X150 + 24X8 =1192MM=1.192 meter

NOTE SLAB COVER HAS NOTHING TO DO WITH CAL.OF STIRRUPS
3) ASSUME cover 30mm (as u have NOT mentioned)
formula to determine cutting length of stirrup is given below
cutting length= (2A+2B)+(24D)
A=LONGER LENGTH OF COLUMN/2 -COVER=400/2-30=170MM
B=SHORTER LENGTH OF COLUMN-2XCOVER=250-30X2=190MM
D= DIAMETER OF STIRRUP BAR IN MM
therefore
cutting length=2X170+2X190 + 24X8 =912MM=0.912 meter EACH

NOTE I HAVE CONSIDERED 8MM DIA STIRRUP BAR EVERY WHERE
UPTO 12MM DIA BARS CAN BE USED AS STIRRUPS GENERALLY
i am a civil engineer. if u r a civil engineer i think u should
by a bookits name is

estimation and costing by B.N.DUTTA u will get alot of
information through this book ....i think no one has been able
to explain the correct method ....good luck

a) let the cover 40 mm.in column,then
cutting length of ring is= 2*(170+320)+2*10*d-10*d
where hooks are= 10d+10d
deduction bend=2*5*d=10d
so length is =1060 mm

If Cutting length of ring is 250-40*2=170
400-40*2=320
Total =170+320*2=980mm+hook calculate 10*8+80
We elongation on the 8mm rod
minus =980+96+96=1172-5*8
1172-40=1132 mm

IN CASE OF COLUMN-
DIM.-200X400mm
CONCRETE COVER-
FOR COLUMN THICKNESS <250mm=25mm
FOR COLUMN THICKNESS >250mm=40mm

LENGHT OF TIE- 2A+2B=2X200+2X400=1200mm

NOW DEDUCT CONCRETE COVER-LENGTH OF TIE-COCNRETE COVER=1200-
2X40=1120MM

ALSO, DEDCUT BENDS- 2D FOR 45degrees
D FOR 90degrees

THEREFORE- CUT LENGTH OF TIE-1120-DX5=1120-2X8=1104mm(NO.
OF BENDS -5 )
Length of Hooks=10d=10x8=80MM
NO. OF hooks=2
Therefore-Length of Hook=2x20=160MM

a) let the cover 40 mm.in column,then
cutting length of ring is= 2*(170+320)+24*d-10*d+5*d
where hooks are= 12d+12d
deduction bend=2*5*d=10d
add 5 times of one dia of bar
so length is =1132mm.

in construction feild make the column rods are uneven ( e.g
1 column we have 6 nos of bars that 6 nos of bars are
varrious level- 1 bar 10';2 bars 9';3 bars 8') what is
resion to put different level if difference are required or
not?

how bridge design is to be start?
what is the preliminary step for design?
which code of practice is to be used for design?
what r the methods used for design?
what r the ivestigation r carried out?
what r the design criteria for design and loading conditions?