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Question
How to calculate the amount of cement & sand required for 
plastering work with ratio 1:4 please give me an answer with 
detailed step.
 Question Submitted By :: Civil-Engineering
I also faced this Question!!     Answer Posted By  
 
Answer
# 1
Area to be plastered=100 m^2
Thickness of plaster=12mm=(12/1000)m= 0.012m
Volume of mortar required= 100 x 0.012= 1.20 m^3
Add 20% extra mortar for filling joint,depressions and
wastage.

Volume of the mortar= [0.20 X 1.20]+ 1.20=1.44 m^3
[Wet Volume]

Increase further by One-third of the volume to get Dry
volume
Quantity becomes= [(1/3) X 1.44]+ 1.44=1.92 m^3

Summation of proportion=1+4=5
For 12mm plastering in 1:4 cement :sand mortar mix:

1)Cement required= 1.92/5= 0.384 cu. m
No. of bags of cement= 0.384/0.0347=11.06 bags

>> 11 bags(say)
Cement used =11 x 50= 550 kg

2)Sand required= [1.92 x (4/5)]= 1.536 cu. m

Important note:
[Weight of 1 bag of cement= 50 kg
Cement should be always measured by weight to avoid
variation.

One 50 kg bag of cement weighs 1440 kg/cu. m
Volume of 1 bag of cement= 50/1440=0.0347 cu. m ]

Therefore to convert Cu. m into No of bags of 50 kg
cement,just divide the volume of cement by 0.0347

Hope u have understood!!!!
 
Is This Answer Correct ?    212 Yes 19 No
Rajarshi Basu
 
Answer
# 2
THE METHOD GIVEN BY Mr.BASU IS SEEMS TO BE APPROPRIATE TO ESTIMATE THE QUANTITY OF CEMENT AND SAND IN PLASTERING. 
Is This Answer Correct ?    29 Yes 11 No
Matrix Civil & Structural
 
 
 
Answer
# 3
Area to be plastered=100 m^2
Thickness of plaster=12mm=(12/1000)m= 0.012m
Volume of mortar required= 100 x 0.012= 1.20 m^3
Add 20% extra mortar for filling joint,depressions and
wastage.

Volume of the mortar= [0.20 X 1.20]+ 1.20=1.44 m^3
[Wet Volume]

Increase further by One-third of the volume to get Dry
volume
Quantity becomes= [(1/3) X 1.44]+ 1.44=1.92 m^3
Summation of proportion=1+4=5
For 12mm plastering in 1:4 cement :sand mortar mix:

1)Cement required= 1.92/5= 0.384 cu. m
No. of bags of cement= 0.384/0.0347=11.06 bags

>> 11 bags(say)
Cement used =11 x 50= 550 kg

2)Sand required= [1.92 x (4/5)]= 1.536 cu. m

Important note:
[Weight of 1 bag of cement= 50 kg
Cement should be always measured by weight to avoid
variation.

One 50 kg bag of cement weighs 1440 kg/cu. m
Volume of 1 bag of cement= 50/1440=0.0347 cu. m ]

Therefore to convert Cu. m into No of bags of 50 kg
cement,just divide the volume of cement by 0.0347
 
Is This Answer Correct ?    9 Yes 2 No
Shalini Mishra
 
Answer
# 4
Yes this formula is near abovet is correct 
Is This Answer Correct ?    8 Yes 2 No
Baldeo M. Sarwe
 

 
 
 
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