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Question
How to calculate the cement, sand quantity for plastering?
(10'x10')10mm thick ratio 1:5. wht"s the formula?
 Question Submitted By :: Civil-Engineering
I also faced this Question!!     Answer Posted By  
 
Answer
# 1
10 feet= 3.05m

area of plaster = 3.05 x 3.05 = 9.3 m2
(convert thickness of plaster into m divide by 1000)
volume of plaster = 9.3 x (10/1000) = 0.09 m3
quantity of cement = 0.09/1+5 =0.09/6 = 0.02 m3
as cement comes in bags of 50 kg therefore volume of one
bag cement = o.0347 m3 (exact)
(or it may be taken 0.034 or 0.035 m3)

no. of cement bags = 0.02/0.0347 = 0.58 bags (almost 1 bag
of cement required for plaster )

quantity of sand = 0.02 x 5 = 0.10 m3

this is exact calculation
you can add 30% extra for wastage etc.
 
Is This Answer Correct ?    201 Yes 40 No
Santosh Singh
 
Answer
# 2
as per thumb rule 1:5 CM

3.04x3.04x0.01=.092416 cu.m
since wall is un-uniform ,increase by 30% ie
.092412 + .0277248= 0.120 cu.m
dry volume increses by 25% = 0.12 + .03 = 0.15 cu.m

total volume of mor= 0.15/6 = .025 cu.m
of cement =0.025x 1440= 36 kg cement
sand = 0.025 X 6= 0.15 cu.m
 
Is This Answer Correct ?    86 Yes 39 No
Srikanth
 
 
 
Answer
# 3
10'=3.04m
mix=1:5,
1/6=.1666+25%+30%=.71cu.m of cement

sand requires=3.5cu.m
plastering area=3.04x3.04x0.01=0.092416cu.m
 
Is This Answer Correct ?    108 Yes 79 No
Sri
 
Answer
# 4
Volume of Wet Mortar = 10 mm X 100 sft.

= 10/1000 X 100/10.76 = 0.093 cu.m.

Add 20% for depressions, joints and wastage
= 0.0186 + 0.093 = 0.112 cu.m.

Volume of Dry Mortar = 1.3 X 0.112 = 0.146 cu.m.= 5.154 cu.ft.

Cement required = 1/6 X 0.146 = 0.024 cu.m. = 0.7 Bag

Sand required = 5/6 X 0.146 = 0.122 cu.m. = 4.30 cu.ft.
 
Is This Answer Correct ?    51 Yes 23 No
Aijaz Hussain, Modi Builders
 
Answer
# 5
breath*depth*0.85/fy. 
Is This Answer Correct ?    121 Yes 111 No
Viplav
 
Answer
# 6
Area to be plastered = 10'*10' = 100'
= 100/10.76 = 9.29sqm
(ie; 1 sqm = 10.76 sqft)
Thickness of mortar layer = 10mm = 0.010m
Volume of mortar required = 9.29*0.010 = 0.09cum
Add 15% for allallowance for calculation of surface and
wastages = (15/100)*.09 = 0.013 cum
Therefore, total volume of mortar required = .09+0.013 =
0.103 cum, say 0.10cum
Sand required for 0.10cum of CM 1:5 = 0.10 cum
Cement required for 0.10 cum of CM 1:5 = (1440/5)*0.10
= 288*0.10 = 28.8 kg
(ie; 1 cum of cement weighs 1440 kg)
 
Is This Answer Correct ?    9 Yes 3 No
Linu T Mathew
 
Answer
# 7
TOTAL QUANTITY OF PLASTERING=3.05*3.05*.01=.093 cu.m
by thumb rule
.75 cu.m of plastering requires =350kg of cement
1750 kg of sand for
the ratio of 1:5 (the weights are calculated with specific
gravities) from this


add 30% extra for wastage and uneveness=.121 cu.m
so for .121 cu.m of plaster requires = 56.5 kg of cement
282.5 kg of sand
 
Is This Answer Correct ?    5 Yes 1 No
Bala Ganesh
 
Answer
# 8
10 FEET =3.048m

3.048*3.048*0.010=0.093cum

sand required =0.093cum(3.28 cft)

Cement req - 1/5*1440*0.093=26.8kg
 
Is This Answer Correct ?    38 Yes 35 No
S.gopal
 
Answer
# 9
10' x 10' x 0.0333'
3.33 cft
Dry metarial in one cft = 1.27 cft
3.33 x 1.27
4.229 cft
sum of ratio = 1+5 = 6
quantity of cement = 1*4.229/6
= 0.7048 cft
volume of one bag = 1.25 cft
=0.7048/1.25
=0.56 cement bag
quantity of sand = 5*4.229/6
= 3.524 cft
 
Is This Answer Correct ?    6 Yes 3 No
Abid Nawaz
 
Answer
# 10
10'=3.04m
mix=1:5,
1/6=.1666+25%+30%=.71cu.m of cement

sand requires=3.5cu.m
plastering area=3.04x3.04x0.01=0.092416cu.m
 
Is This Answer Correct ?    3 Yes 1 No
Naga
 

 
 
 
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