area of plaster = 3.05 x 3.05 = 9.3 m2
(convert thickness of plaster into m divide by 1000)
volume of plaster = 9.3 x (10/1000) = 0.09 m3
quantity of cement = 0.09/1+5 =0.09/6 = 0.02 m3
as cement comes in bags of 50 kg therefore volume of one
bag cement = o.0347 m3 (exact)
(or it may be taken 0.034 or 0.035 m3)

no. of cement bags = 0.02/0.0347 = 0.58 bags (almost 1 bag
of cement required for plaster )

quantity of sand = 0.02 x 5 = 0.10 m3

this is exact calculation
you can add 30% extra for wastage etc.

10' x 10' x 0.0333'
3.33 cft
Dry metarial in one cft = 1.27 cft
3.33 x 1.27
4.229 cft
sum of ratio = 1+5 = 6
quantity of cement = 1*4.229/6
= 0.7048 cft
volume of one bag = 1.25 cft
=0.7048/1.25
=0.56 cement bag
quantity of sand = 5*4.229/6
= 3.524 cft

Area to be plastered = 10'*10' = 100'
= 100/10.76 = 9.29sqm
(ie; 1 sqm = 10.76 sqft)
Thickness of mortar layer = 10mm = 0.010m
Volume of mortar required = 9.29*0.010 = 0.09cum
Add 15% for allallowance for calculation of surface and
wastages = (15/100)*.09 = 0.013 cum
Therefore, total volume of mortar required = .09+0.013 =
0.103 cum, say 0.10cum
Sand required for 0.10cum of CM 1:5 = 0.10 cum
Cement required for 0.10 cum of CM 1:5 = (1440/5)*0.10
= 288*0.10 = 28.8 kg
(ie; 1 cum of cement weighs 1440 kg)

TOTAL QUANTITY OF PLASTERING=3.05*3.05*.01=.093 cu.m
by thumb rule
.75 cu.m of plastering requires =350kg of cement
1750 kg of sand for
the ratio of 1:5 (the weights are calculated with specific
gravities) from this

add 30% extra for wastage and uneveness=.121 cu.m
so for .121 cu.m of plaster requires = 56.5 kg of cement
282.5 kg of sand