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Question
how to calculate sand, cement quantity for plastering (1:5)? what"s the formula?
 Question Submitted By :: Civil-Engineering
I also faced this Question!!     Answer Posted By  
 
Answer
# 1
Let Area to be plastered=100 m^2
& Thickness of plaster= 12mm=(12/1000)m= 0.012m
Volume of mortar required= 100 x 0.012= 1.20 m^3
Add 20% extra mortar for filling joint,depressions and
wastage.

Volume of the mortar= [0.20 X 1.20]+ 1.20=1.44 m^3
[Wet Volume]

Increase further by One-third of the volume to get Dry
volume
Quantity becomes= [(1/3) X 1.44]+ 1.44=1.92 m^3

Summation of proportion=1+5=6
For 12mm plastering in 1:5 cement:sand mortar mix,

1)Cement required= 1.92/6= 0.32 cu. m
No. of bags of cement= 0.320/0.0347=9.22 bags
>>9 bags(say)
Kgs of cement required=9 x 50= 450 kg (approx)

2)Sand required= [1.92 x (5/6)]= 1.60 cu. m


[Weight of 1 bag of cement= 50 kg
Cement should be always measured by weight to avoid
variation.

One 50 kg bag of cement weighs 1440 kg/cu. m
Volume of 1 bag of cement= 50/1440=0.0347 cu. m ]

Therefore to convert Cu. m into No of bags of 50 kg
cement,just divide the volume of cement by 0.0347
 
Is This Answer Correct ?    151 Yes 9 No
Rajarshi Basu
 
Answer
# 2
cement:sand= 1:5
for 1cum= 1/6
=0.166
so cement for 1 cum=0.166cum
but volume of 1 cement bag is=.033cum
bag required per cum is=.166/.033
=5 bags
sand required is=0.166*5
=0.833 cum
 
Is This Answer Correct ?    70 Yes 36 No
Ashwin
 
 
 
Answer
# 3
let Area to be plastered=100 m^2
& Thickness of plaster= 12mm=(12/1000)m= 0.012m
Volume of mortar required= 100 x 0.012= 1.20 m^3
Add 20% extra mortar for filling joint,depressions and
wastage.

Volume of the mortar= [0.20 X 1.20]+ 1.20=1.44 m^3
[Wet Volume]

Increase further by One-third of the volume to get Dry
volume
Quantity becomes= [(1/3) X 1.44]+ 1.44=1.92 m^3

Summation of proportion=1+5=6
For 12mm plastering in 1:5 cement:sand mortar mix,

1)Cement required= 1.92/6= 0.32 cu. m
No. of bags of cement= 0.320/0.0347=9.22 bags
>>9 bags(say)
Kgs of cement required=9 x 50= 450 kg (approx)

2)Sand required= [1.92 x (5/6)]= 1.60 cu. m


[Weight of 1 bag of cement= 50 kg
Cement should be always measured by weight to avoid
variation.

One 50 kg bag of cement weighs 1440 kg/cu. m
Volume of 1 bag of cement= 50/1440=0.0347 cu. m ]

Therefore to convert Cu. m into No of bags of 50 kg
cement,just divide the volume of cement by 0.0347
 
Is This Answer Correct ?    33 Yes 6 No
Sandeep Tv
 
Answer
# 4
above ansewr is corect 
Is This Answer Correct ?    30 Yes 6 No
Munir
 
Answer
# 5
anser plz
 
Is This Answer Correct ?    36 Yes 17 No
Yuy
 
Answer
# 6
1:5 PLASTERING CEMENT REQUIRED IS 288 KGS 
Is This Answer Correct ?    34 Yes 22 No
Jegan
 
Answer
# 7
why should we have to take 20% of wet mortar & 1/3rd of Dry mortar......is there eny code for that...or plz tell me where it coms from......plz clear me .... 
Is This Answer Correct ?    3 Yes 1 No
Hidayathulla
 
Answer
# 8
Let Area to be plastered=100 m^2
& Thickness of plaster= 12mm=(12/1000)m= 0.012m
Volume of mortar required= 100 x 0.012= 1.20 m^3
Add 20% extra mortar for filling joint,depressions and
wastage.

Volume of the mortar= [0.20 X 1.20]+ 1.20=1.44 m^3
[Wet Volume]

Increase further by One-third of the volume to get Dry
volume
Quantity becomes= [(1/3) X 1.44]+ 1.44=1.92 m^3

Summation of proportion=1+5=6
For 12mm plastering in 1:5 cement:sand mortar mix,

1)Cement required= 1.92/6= 0.32 cu. m
No. of bags of cement= 0.320/0.0347=9.22 bags
>>9 bags(say)
Kgs of cement required=9 x 50= 450 kg (approx)

2)Sand required= [1.92 x (5/6)]= 1.60 cu. m


[Weight of 1 bag of cement= 50 kg
Cement should be always measured by weight to avoid
variation.

One 50 kg bag of cement weighs 1440 kg/cu. m
Volume of 1 bag of cement= 50/1440=0.0347 cu. m ]

Therefore to convert Cu. m into No of bags of 50 kg
cement,just divide the volume of cement by 0.0347
 
Is This Answer Correct ?    3 Yes 2 No
Yogesh Khandelwal
 
Answer
# 9
Area 100 SFT 100*1.54 =154 CFT
Ratio 1:5 Sum of ratio 1+5=6
Cement 1/6*154 = 25.66 CFT
Bag 25.66/1.25=20.528 Say 21 Bags
Sand 5/6*154 =128.33 CFT
 
Is This Answer Correct ?    1 Yes 0 No
Saqib
 
Answer
# 10
1:5 proportion for (1)cement @ 40kg): (5)sand @ 33 kg(S.G
@2.6) gives you approximate volume of 0.142 cubic meter.

if you want exact volume, provide the specific gravity of
your materials and include air content and water for your
volume...
 
Is This Answer Correct ?    0 Yes 0 No
Adz
 

 
 
 
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