cement:sand= 1:5
for 1cum= 1/6
=0.166
so cement for 1 cum=0.166cum
but volume of 1 cement bag is=.033cum
bag required per cum is=.166/.033
=5 bags
sand required is=0.166*5
=0.833 cum

Let Area to be plastered=100 m^2
& Thickness of plaster= 12mm=(12/1000)m= 0.012m
Volume of mortar required= 100 x 0.012= 1.20 m^3
Add 20% extra mortar for filling joint,depressions and
wastage.

Volume of the mortar= [0.20 X 1.20]+ 1.20=1.44 m^3
[Wet Volume]

Increase further by One-third of the volume to get Dry
volume
Quantity becomes= [(1/3) X 1.44]+ 1.44=1.92 m^3

Summation of proportion=1+5=6
For 12mm plastering in 1:5 cement:sand mortar mix,

1)Cement required= 1.92/6= 0.32 cu. m
No. of bags of cement= 0.320/0.0347=9.22 bags
>>9 bags(say)
Kgs of cement required=9 x 50= 450 kg (approx)

2)Sand required= [1.92 x (5/6)]= 1.60 cu. m

[Weight of 1 bag of cement= 50 kg
Cement should be always measured by weight to avoid
variation.

One 50 kg bag of cement weighs 1440 kg/cu. m
Volume of 1 bag of cement= 50/1440=0.0347 cu. m ]

Therefore to convert Cu. m into No of bags of 50 kg
cement,just divide the volume of cement by 0.0347

let Area to be plastered=100 m^2
& Thickness of plaster= 12mm=(12/1000)m= 0.012m
Volume of mortar required= 100 x 0.012= 1.20 m^3
Add 20% extra mortar for filling joint,depressions and
wastage.

Volume of the mortar= [0.20 X 1.20]+ 1.20=1.44 m^3
[Wet Volume]

Increase further by One-third of the volume to get Dry
volume
Quantity becomes= [(1/3) X 1.44]+ 1.44=1.92 m^3

Summation of proportion=1+5=6
For 12mm plastering in 1:5 cement:sand mortar mix,

1)Cement required= 1.92/6= 0.32 cu. m
No. of bags of cement= 0.320/0.0347=9.22 bags
>>9 bags(say)
Kgs of cement required=9 x 50= 450 kg (approx)

2)Sand required= [1.92 x (5/6)]= 1.60 cu. m

[Weight of 1 bag of cement= 50 kg
Cement should be always measured by weight to avoid
variation.

One 50 kg bag of cement weighs 1440 kg/cu. m
Volume of 1 bag of cement= 50/1440=0.0347 cu. m ]

Therefore to convert Cu. m into No of bags of 50 kg
cement,just divide the volume of cement by 0.0347

suppose area=100 sft
ratio 1:5
sum of ratio is 1+5=6
for cement=1/6*100=16.666
so 16.666*1.54=25.666
for cement bags=25.666/1.25=20.5333
so say 21 bags of cement

my client's 10 year old building have been affected by the
neighbor new building construction with out set back.Old
building cantilever bldg hanged by 3". It is supported by
introducing 2 rcc columns & beams.Now how to conceal the cracks?

1)define the critical items in rcc framed G+18 bldg. as Cr
Activity 1,Cr Activity 2,Cr Activity 3...etc.
2)on what logic is MSP and Primavera planning based.FS SF
FF...