Hey people
It will not give any syntax error more specifically.. it
will not give any type of error..
The output depends on the compiler u r using...
if it is GCC of linux then O/p== garbage value
there are compilers which will give the last integer value
assigned..
example...
i=30;
printf("%d");
will give ouput 30... but for Gcc it will be garbage value.
When insufficent argumrnts r give 2 c compiler it give
arbitrary answers
in turbo c it gives o/p =0
in other compiler it trys 2 read values from last stack top
i.e garbage
some compiler can may even crash
class HasStatic {
static int I;
};
Referring to the sample code above, what is the appropriate
method of defining the member variable "I", and assigning it
the value 10, outside of the class declaration?
a) HasStatic I = 10;
b) int static I = 10;
c) static I(10);
d) static I = 10;
e) int HasStatic::I = 10;
class X
{
private:
int a;
protected:
X(){cout<<"X constructor was called"<<endl;}
~X(){cout<<"X destructor was called"<<endl}
};
Referring to the code above, which one of the following
statements regarding "X" is TRUE?
a) X is an abstract class.
b) Only subclasses of X may create X objects.
c) Instances of X cannot be created.
d) X objects can only be created using the default copy
constructor.
e) Only friends can create instances of X objects.
int f() {
int I = 12;
int &r = I;
r += r / 4;
int *p = &r;
*p += r;
return I;
}
Referring to the sample code above, what is the return value
of the function "f()"?
a) 12
b) 15
c) 24
d) 17
e) 30
1. What does the following do:
void afunction(int *x)
{
x=new int;
*x=12;
}
int main()
{
int v=10;
afunction(&v);
cout<<v;
}
a) Outputs 12
b) Outputs 10
c) Outputs the address of v
this is to swap to strings....but in output the whole
strings are swapped leaving first as it is...why it is so
#include<iostream.h>
int main()
{
char a[]="ajeet";
char b[]="singh";
long x=*a;
long y=*b;
cout<<x<<":"<<y;
x=x+y;
y=x-y;
x=x-y;
*a=x;
*b=y;
cout<<x<<":"<<y;
cout<<&a<<endl;
cout<<&b<<endl;
}