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                 TATA -IBM
                -----------
              
	      LETTER SERIES
                                         
	                                    answers
			     -             -------
 1)e e f g g h i i ---                       j    

 2)a z a y b z b y c ---     a e x y z       z

 3)d e f d e f g h i ---     d e f g h       g

 4)c d e x y z f g h x y z   i j k l m       i

 5)de f de g d e ---         d j z h i       h

 6)a b c z a b c y a b c --- a b x y z       x

 7)d g b h i b j k b ----     b e l m n      l

 8)t s p t s q t s --- r s t v w             r

 9)q a r b s a t a r b ----    a b e r s     s

 10)b c c d e e f g -- e f g h i             g

 11)e f h i k l ---    m n o p q             n

 12)a b cc d e ff g -- efghi                 h

 13)a m n b op c ---   depqr                 q

 14)ttt sss qqq p ---  opqrs                 p

 15)ddffhhjj---        ijklm                 l

 16)mnmnklopopkl ----- kopqr                 q

 17)cddeeefff---       efghi                 f

 18)gfde----           bcfgh                 c
 
 19)dfhjl -----        jklmn                 n

 20)abcijdefij----     ghijk                 g

 21)efgefghefghi ----                        e

 22)bcbdedffghi ----   fghjk                 h

 23)aababccdc  ---     cdefg                 d

 24)aibcidef ---       efghi                 i

 25)cehl ---           opqrs                 q

 26)abdehimn ---       pqrst                 s

 27)becfdge ---        efghi                 h

 28)agbhc ----         dfghi                 i

 29)adhko ---          pqrst                 r

 30)efghjklno ---      pqrst                 q

31)aeibf ---           cdgij                 j

 32)aedhg--            hijkl                 k

 33)zdwgt ---          hijkl                 j

 34)zeiyijxj---        ijklm                 k

 35)dqreuvg---         vwxyz                 y

 36)ksjtiuh---         vwxyz                 v

37)rsjtuhvw---        cdefg                  f


 38)ieajfbk ----       cdefg                 g

 39)hebijej ----       ghijk                 g

 40)njfmiel ---        dhijm                 h



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1)
	   main()
		{
		 char *p1="name";
		 char *p2;
		 p2=(char*)malloc(20);
		 while(*p2++ = *p1++);
		 printf("%s\n",p2);
		}
		  Ans:empty string.
2)
	    main()
		{
		   int x=20,y=35;
		   x=y++ + x++;
		   y= ++y + ++x;
		   printf("%d%d\n",x,y);
		 }
		  Ans : 57 ,94
 3)
		 main()
		  {
		    int x=5;
		    printf("%d%d%d\n",x,x<<2,x>>2);
		  }
		  ans: 5,20,16
4)
		 #define swap(a,b) a=a+b;b=a-b;a=a-b;
		 main()
		 {
		  int x=5;y=10;
		  swap1(x,y);
		  printf("%d %d\n",x,y);
		  swap2(x,y);
		  printf("%d %d\n",x,y);
		 }
	    int swap2(int a, int b)
	    {
		int temp;
		temp=a;
		b=a;
		a=temp;
		return;
	    }
		  like that
		    ans: 10 ,5
				10 ,5
 5)
	main()
	 {
	   char *ptr = " Ramco Systems"
	   (*ptr)++;
	   printf("%s\n",ptr);
	   ptr++;
	   printf("%s\n",ptr);
	  }
	   Ans:  Samco Systems
		    amco systems
 6)
	  main()
	  {
	   char s1[]="Ramco";
	   char s2[]= "systems";
	   printf("%s",s1);
	  }
	  Ans: compilation error giving that it can not 
modified Lvalue.
7)
	main()
	 {
	  char *p1;
	  char *p2;
	  p1=(char *)malloc(25);
	  p2=(char *)malloc(25);
	  strcpy(p1,"Ramco");
	  strcpy(p2,"systems");
	  strcat(p1,p2);
	  printf("%s",p1);
	 }
	  Ans: Ramcosystems



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8)
   The following variable is available in file1.c
	static int average float;
	Ans: all the functions in the file1.c can access 
the variable.
9)
    Ans : [2] . extern int x;
    check the answer.
10)  Another problem with
	#define TRUE 0
	 somecode.
	 while(TRUE)
	 {
	  somecode
	 }
	 This will not go into the loop as TRUE is defined 
as 0.
	 Ans : None of the above i.e (D).
 11)
	   Ans :
		 [4]. A question in structures where the 
members are dd,mm,yy.
		   mm:dd:yy
		   09:07:97
15) structure kswap
	Ramco India
	Ramco Systems Corporation
	Ramco .... Limited.

	After swaping  the result will be
	First two will be swaped
	Ramco Systems Corporation.
	Ramco India
	Ramco .... Limited.
16)  int x;
	 main()
	  { int x=10;
		 x++;
		 change-value(x);
		 x++;
		 modify-value();
		 printf("First output:%d\n",x);

	   x++;
	   change-value(x);
	   printf("secpnd output:%d\n",x);
	   modify-value();
	   printf("Third output:%d\n",x);
	}
	  modify-value()
	  {
	   return(x+=10);
	  }
	  change-value()
	  {
	   return(x+=1);
	  }
	Ans: 12 , 1 , 1
17)  main()
	 {
	  int x=10;y=15;
	  x = x++;
	  y = ++y;
	  printf("%d %d\n",x,y);
	 }
	 Ans: 11, 16
18)
	main()
	 {
	  int a=0;
	  if(a==0) printf("Ramco Systems\n");
	  printf("Ramco Systems\n");
	 }
	Ans: only one time "Ramco Systems" will be printed.





TISL Placement Papers | TISL Interview Procedure | TISL 
Aptitude Questions | TISL Technical Questions | TISL 
Interview Questions