the below program is for getting two numbers as input
(decimal format) and then the below program will convert in
binary and add WITHOUT ANY ARITHMETIC OPERATORS.....



#include<stdio.h>
#include<conio.h>
#define HIGH 1
#define LOW 0
void main()
{
long c[32],i,n,a,b,k,m,A,CARRY=0;
clrscr();
n=31;
printf("enter the value of a&b:");
scanf("%ld%ld",&a,&b);
for(i=0;i<32;i++)
{
  k=((a>>i)&1);
  m=((b>>i)&1);
   if(!(CARRY^HIGH))
   {
    c[n]=((CARRY^k)^m);
      if(!(k^HIGH)||!(m^HIGH))
       CARRY=1;
      else
       CARRY=0;
   }
   else if(!(k^HIGH) && !(m^HIGH))
   {
    CARRY=1;
    c[n]=k^m;
   }
   else if(!(k^LOW)||!(m^LOW))
   {
    if(!(CARRY^HIGH))
    {
     c[n]=((CARRY^k)^m);
     CARRY=0;
    }
    else
    c[n]=k^m;
   }
  n--;
}
for(i=0;i<32;i++)
printf("%d",c[i]);
getch();
}


thank u