vector is synchronized . collection object and variable 
slow acess. muntable
array list is never snchronized. collection variable fast 
acess

Vector is synchronized and compare to array list this slow 
access, by defaulst the vector is 10,this is legacy class 
Where as arraylist is unsynchronized and fast random 
access,in arraylist there is no default size automatically 
it is growable once the object is created it will be 
allocated,this is advanced class.

main()
{

if(printf("hello"))

}

int main()
{

if(printf("Hello"))
{
//Null statement
}

}

int main()
{
  if(printf("Hello"))
   {
    
   }
}

Answer 2nd is correct;

There are no events in LSMW. LSMW is a tool used to migrate
data from Non-sap to sap and sap to sap Systems. we can send
the data using lsmw with several options( like direct
input,batch input, BAPI's and IDOC's).

Events in LSMW.
1) Begin_of_transaction:
2) End_of_transaction
3) Begin_of_record.
4) End_of_record.

Events in LSMW

1.BEGIN_OF_PROCESSING - Before the beginning of data 
processing 
2.BEGIN_OF_TRANSACTION - Before the beginning of 
transaction data processing 
3.__BEGIN_OF_RECORD__ Before applying the conversion rules 
for a source structure
4.END_OF_RECORD_ After applying the conversion rules for a 
source structure
5.__END_OF_TRANSACTION__After finishing transaction 
processing 
6.END_OF_PROCESSING__ After finishing data processing

There are not any events in LSMW. SAP has provided a tool
named LSMW which convert the legacy data into the required
sap format and update the database.....

Let the revolutins made by rear wheel be: x
then revolution by front wheel will be: x+10

Now, the distance covered by both will be same.
So,
    7(x+10)=9x
    7x+70=9x
    70=2x
    35=x

So the total distance is 7*35 i.e. 315 feets.

Revolutions of front wheel=10
then the revolutions of back wheel is same as front wheel.
But actual distance covered by both of them is

Let as assume distance covered by wheel is x
x=((10*7)/2)*7=245 feets.

Let the revolutins made by bigger wheel is: x
then revolution by smaller wheel will be: x+10

Now, the distance covered by both wheels will be same.
So,
    7(x+10)=9x
    7x+70=9x
    70=2x
    35=x
so distance travelled=9*35=315
or 7*45=315

Yup 315 is the rite answer